Question

11．解不等式組$\left\{\begin{array}{l}{2≤3x}\\{x-\frac{2x+1}{3}＞1-\frac{3x-2}{5}}\end{array}\right.$．

Answer 1

分析 先化簡(jiǎn)不等式組的各項(xiàng)，然后根據(jù)不等式的性質(zhì)和求不等式解集的方法解答即可．

解答 解：$\left\{\begin{array}{l}{2≤3x}\\{x-\frac{2x+1}{3}＞1-\frac{3x-2}{5}}\end{array}\right.$
化簡(jiǎn)為，$\left\{\begin{array}{l}{2≤3x}\\{7x＞13}\end{array}\right.$
$\left\{\begin{array}{l}{x≥\frac{2}{3}}\\{x＞\frac{13}{7}}\end{array}\right.$
所以，不等式組的解是：x$＞\frac{13}{7}$．

點(diǎn)評(píng) 本題重點(diǎn)考查了對(duì)解一元一次不等式組的應(yīng)用，注意“同大取大”．