(2012?平?jīng)觯┟撌接嬎悖芎喫愕囊喫悖?
1
1
10
-
1
4
-0.75
1
8
×58+
1
8
×41+
1
8
2
5
×
1
5
+40%×
4
5
5
9
÷5+5÷
5
9
7
12
-
1
3
)×
2
7
3.5×9.9.
分析:(1)根據(jù)連減的性質(zhì)進行計算;
(2)根據(jù)乘法分配律進行計算;
(3)根據(jù)乘法分配律進行計算;
(4)先算除法,再算加法;
(5)先算減法,再算乘法;
(6)根據(jù)乘法分配律進行計算;
解答:解:
(1)1
1
10
-
1
4
-0.75,
=1
1
10
-(
1
4
+0.75),
=1
1
10
-1,
=
1
10


(2)
1
8
×58+
1
8
×41+
1
8
,
=(58+41+1)×
1
8
,
=100×
1
8

=12.5;

(3)
2
5
×
1
5
+40%×
4
5
,
=0.4×
1
5
+0.4×
4
5
,
=0.4×(
1
5
+
4
5
),
=0.4×1,
=0.4;

(4)
5
9
÷5+5÷
5
9
,
=
1
9
+9,
=9
1
9
;

(5)(
7
12
-
1
3
)×
2
7
,
=
1
4
×
2
7
,
=
1
14


(6)3.5×9.9,
=3.5×(10-0.1),
=3.5×10-3.5×0.1,
=35-0.35,
=34.65.
點評:四則運算,先弄清運算順序,然后再進一步計算即可,能簡算的要簡算.
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