9.2×12
1
2
=
37
8
37
÷9=
72
73
×21=
5.089×
1
100
=
59×
27
58
=
12
5
11
÷
1
11
=
3
7
×
1
8
÷
3
7
×
1
8
=
14
19
+(
6
19
-
18
29
)÷1
1
5
-
14
29
=
34×3.1+5.1×14-6
4
5
=
1
6
+
1
12
+
1
20
+
1
30
+
1
42
=
3+
3
2
+
3
4
+
3
8
+
3
16
+
3
32
+
3
64
=
4.25×1.32×0.75÷(1
8
25
×1
3
16
)=
分析:(1)先把分?jǐn)?shù)化成小數(shù),再計算;
(2)(6)根據(jù)除以一個數(shù)等于乘這個數(shù)的倒數(shù)計算;
(3)先把
72
73
化成1-
1
73
,再運用乘法分配律簡算;
(4)把5.089的小數(shù)點向左移動兩位即可;
(5)把59分解成58+1,再運用乘法分配律簡算;
(7)先把除法變成乘法,再運用乘法結(jié)合律簡算;
(8)先把除法變成乘法,運用乘法分配律簡算,再運用加法交換律和減法的性質(zhì)簡算;
(9)先算乘法,再算加減法;
(10)
1
6
=
1
2
-
1
3
1
12
=
1
3
-
1
4
…由此化簡求解;
(11)先提取因數(shù)3,然后再把剩下的分?jǐn)?shù)分解;如
1
4
=
1
2
-
1
4
,
1
8
=
1
4
-
1
8
…;
(12)先根據(jù)除法的性質(zhì),去掉小括號,再運用乘法結(jié)合律簡算.
解答:解:(1)9.2×12
1
2
=115;

(2)37
8
37
÷9,
=
1377
37
×
1
9

=
153
37
;

(3)
72
73
×21,
=(1-
1
73
)×21,
=1×21-
1
73
×21,
=21-
21
73

=20
52
73
;

(4)5.089×
1
100
=0.05089;

(5)59×
27
58

=(58+1)×
27
58
,
=58×
27
58
+1×
27
58
,
=27+
27
58
,
=27
27
58
;

(6)12
5
11
÷
1
11

=
137
11
×11,
=137;

(7)
3
7
×
1
8
÷
3
7
×
1
8
,
=(
3
7
×
7
3
)×(
1
8
×
1
8
),
=1×
1
64

=
1
64
;

(8)
14
19
+(
6
19
-
18
29
)÷1
1
5
-
14
29

=
14
19
+(
6
19
-
18
29
)×
5
6
-
14
29
,
=
14
19
+
6
19
×
5
6
-
18
29
×
5
6
-
14
29
,
=
14
19
+
5
19
-
15
29
-
14
29
,
=(
14
19
+
5
19
)-(
15
29
+
14
29
),
=1-1,
=0;

(9)34×3.1+5.1×14-6
4
5
,
=105.4-71.4-6.8,
=34-6.8,
=40.8;

(10)
1
6
+
1
12
+
1
20
+
1
30
+
1
42
,
=
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5
+
1
6
-
1
7
,
=
1
2
-
1
7

=
5
14
;

(11)3+
3
2
+
3
4
+
3
8
+
3
16
+
3
32
+
3
64
,
=3×(1+
1
2
+
1
4
+
1
8
+
1
16
+
1
32
+
1
64
),
=3×[1+(1-
1
2
)+(
1
2
-
1
4
)+(
1
4
-
1
8
)+(
1
8
-
1
16
)+(
1
16
-
1
32
)+(
1
32
-
1
64
)],
=3×(+1-
1
2
+
1
2
-
1
4
+
1
4
-
1
8
+
1
8
-
1
16
+
1
16
-
1
32
+
1
32
-
1
64
),
=3×(1+1-
1
64
),
=3×1
63
64
,
=
381
64
;

(12)4.25×1.32×0.75÷(1
8
25
×1
3
16
),
=4.25×1.32×0.75÷1.32÷1.1875,
=(4.25×0.75÷1.1875)×(1.32×1.32),
=1.7×1,
=1.7.
點評:完成本題要注意分析式中數(shù)據(jù),運用合適的簡便方法計算.
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