例2.已知函數(shù)y=-上恒有y/>0,求a的范圍 查看更多

 

題目列表(包括答案和解析)

若函數(shù)f(x)對(duì)定義域中任意x均滿足f(x)+f(2a-x)=2b,則稱函數(shù)y=f(x)的圖象關(guān)于點(diǎn)(a,b)對(duì)稱.
(Ⅰ)已知函數(shù)的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,求實(shí)數(shù)m的值;
(Ⅱ)已知函數(shù)g(x)在(-∞,0)∪(0,+∞)上的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,且當(dāng)x∈(0,+∞)時(shí),g(x)=x2+ax+1,求函數(shù)g(x)在(-∞,0)上的解析式;
(Ⅲ)在(Ⅰ)、(Ⅱ)的條件下,當(dāng)t>0時(shí),若對(duì)任意實(shí)數(shù)x∈(-∞,0),恒有g(shù)(x)<f(t)成立,求實(shí)數(shù)a的取值范圍.

查看答案和解析>>

若函數(shù)f(x)對(duì)定義域中任意x均滿足f(x)+f(2a-x)=2b,則稱函數(shù)y=f(x)的圖象關(guān)于點(diǎn)(a,b)對(duì)稱.
(Ⅰ)已知函數(shù)的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,求實(shí)數(shù)m的值;
(Ⅱ)已知函數(shù)g(x)在(-∞,0)∪(0,+∞)上的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,且當(dāng)x∈(0,+∞)時(shí),g(x)=x2+ax+1,求函數(shù)g(x)在(-∞,0)上的解析式;
(Ⅲ)在(Ⅰ)、(Ⅱ)的條件下,當(dāng)t>0時(shí),若對(duì)任意實(shí)數(shù)x∈(-∞,0),恒有g(shù)(x)<f(t)成立,求實(shí)數(shù)a的取值范圍.

查看答案和解析>>

若函數(shù)f(x)對(duì)定義域中任意x均滿足f(x)+f(2a-x)=2b,則稱函數(shù)y=f(x)的圖象關(guān)于點(diǎn)(a,b)對(duì)稱.
(Ⅰ)已知函數(shù)數(shù)學(xué)公式的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,求實(shí)數(shù)m的值;
(Ⅱ)已知函數(shù)g(x)在(-∞,0)∪(0,+∞)上的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,且當(dāng)x∈(0,+∞)時(shí),g(x)=x2+ax+1,求函數(shù)g(x)在(-∞,0)上的解析式;
(Ⅲ)在(Ⅰ)、(Ⅱ)的條件下,當(dāng)t>0時(shí),若對(duì)任意實(shí)數(shù)x∈(-∞,0),恒有g(shù)(x)<f(t)成立,求實(shí)數(shù)a的取值范圍.

查看答案和解析>>

解答題

若函數(shù)f(x)對(duì)定義域中任意x均滿足f(x)+f(2a-x)=2b,則稱函數(shù)y=f(x)的圖象關(guān)于點(diǎn)(a,b)對(duì)稱.

(1)

已知函數(shù)的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,求實(shí)數(shù)m的值;

(2)

已知函數(shù)g(x)在(-∞,0)Y(0,+∞)上的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,且當(dāng)x∈(0,+∞)時(shí),g(x)=x2+ax+1,求函數(shù)g(x)在(-∞,0)上的解析式;

(3)

在(1)、(2)的條件下,當(dāng)t>0時(shí),若對(duì)實(shí)數(shù)任意x∈(-∞,0),恒有g(shù)(x)<f(t)成立,求實(shí)數(shù)a的取值范圍.

查看答案和解析>>

若函數(shù)f(x)對(duì)定義域中任意x均滿足f(x)+f(2a-x)=2b,則稱函數(shù)y=f(x)的圖象關(guān)于點(diǎn)(a,b)對(duì)稱.
(Ⅰ)已知函數(shù)f(x)=
x2+mx+mx
的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,求實(shí)數(shù)m的值;
(Ⅱ)已知函數(shù)g(x)在(-∞,0)∪(0,+∞)上的圖象關(guān)于點(diǎn)(0,1)對(duì)稱,且當(dāng)x∈(0,+∞)時(shí),g(x)=x2+ax+1,求函數(shù)g(x)在(-∞,0)上的解析式;
(Ⅲ)在(Ⅰ)、(Ⅱ)的條件下,當(dāng)t>0時(shí),若對(duì)任意實(shí)數(shù)x∈(-∞,0),恒有g(shù)(x)<f(t)成立,求實(shí)數(shù)a的取值范圍.

查看答案和解析>>


同步練習(xí)冊(cè)答案