題目列表(包括答案和解析)
根據(jù)短文內(nèi)容,從下框的A---F選項(xiàng)中選出能概括每一段主題的最佳選項(xiàng)。選項(xiàng)中有一項(xiàng)為多余項(xiàng)。
Bill,Emy,Ben,Brigitte和Susan五個(gè)人想購買雜志。閱讀下面六本雜志(A、B、C、D、E和F ) 的介紹,選出符合各人需要的最佳選項(xiàng)。選項(xiàng)中有一項(xiàng)是多余選項(xiàng)。
注意: 該題要求做在答題卡上。選擇E,則涂黑A+B, 選擇F,則涂黑A+C
【小題1】Bill travels a lot when he was younger.Now that he has stopped his work,he enjoys reading about foreign people,places and customs even if he has already visited that part of the world.
【小題2】
Emy is a university student studying Italian and Politics.She doesn’t have much time to read anything very detailed but she is looking for something with plenty of news and information.
【小題3】Ben serves as an assistant to the general manager of an American company in Los Angeles.He is very interested in management and the use of high technology.
【小題4】
Up till now Brigitte has never traveled far so this year she has decided to go abroad for the first time.The travel agent suggests that she should read about various countries first before choosing her holiday.
【小題5】Susan likes shopping.She is interested in buying clothes and she needs to be offered advice on clothes.
A.Discover News magazine of science devoted to the wonders and stories of modem science,written for the educated general reader.Published by Disney Magazine Publishing CO.,Discover tells many of the same stories professionals read in Scientific American.A truly delightful family science magazine,each issue brings to light new and newsworthy topics to make dinnertime and water-cooler conversations interesting. |
B.World Travel This weekly magazine can bring the world to your home.Have you ever wondered what the Chinese eat for breakfast? Did you know that the Sahara Desert is getting bigger every year? This fascinating magazine,full of color photographs,is your window to the world. |
C.Self Published by Conde Nast Publications Inc.,Self is a handbook devoted to women’s overall physical and mental health.Every issue contains usable articles such as “Style Lab”.in which wearable clothes are mixed and matched on non—models and the “Eat—Right Road Map”.with tips on how to eat properly. |
D.Foreign Parts |
已知命題“若函數(shù)在是增函數(shù),則”,則下列結(jié)論正確的是
A.否命題是“若函數(shù)在是減函數(shù),則”,是真命題
B. 逆命題是“若,則函數(shù)在是增函數(shù)”, 是假命題
C. 逆否命題是“若,則函數(shù)在是減函數(shù)”, 是真命題
D. 逆否命題是“若,則函數(shù)在不是增函數(shù)”, 是真命題
設(shè)隨機(jī)變量∽∽,記,則
A. B. C. D. 的大小關(guān)系不定
若某救災(zāi)物資儲(chǔ)備基地的儲(chǔ)備物資中,節(jié)水設(shè)施、救生器具、凈水劑的比重較大,則該基地最有可能是
A.武漢 B.成都 C.西安 D.昆明
一人站在體重計(jì)上稱體重,保持立正姿勢稱得體重為G,當(dāng)其緩慢地把一條腿平直伸出臺(tái)面,體重計(jì)指針穩(wěn)定后讀數(shù)為G/,則( )
A.G>G/ B.G<G/ C.G=G/’ D.無法判定
1.解析:,故選A。
2.解析:抽取回族學(xué)生人數(shù)是,故選B。
3.解析:由,得,此時(shí),所以,,故選C。
4.解析:∵∥,∴,∴,故選C。
5.解析:設(shè)公差為,由題意得,;,解得或,故選C。
6.解析:∵雙曲線的右焦點(diǎn)到一條漸近線的距離等于焦距的,∴,又∵,∴,∴雙曲線的漸近線方程是,故選D.
7.解析:∵、為正實(shí)數(shù),∴,∴;由均值不等式得恒成立,,故②不恒成立,又因?yàn)楹瘮?shù)在是增函數(shù),∴,故恒成立的不等式是①③④。故選C.
8.解析:∵,∴在區(qū)間上恒成立,即在區(qū)間上恒成立,∴,故選D。
9.解析:∵
,∴此函數(shù)的最小正周期是,故選C。
10.解析:如圖,∵正三角形的邊長為,∴,∴,又∵,∴,故選D。
11.解析:∵在區(qū)間上是增函數(shù)且,∴其反函數(shù)在區(qū)間上是增函數(shù),∴,故選A
12.解析:如圖,①當(dāng)或時(shí),圓面被分成2塊,涂色方法有20種;②當(dāng)或時(shí),圓面被分成3塊,涂色方法有60種;
③當(dāng)時(shí),圓面被分成4塊,涂色方法有120種,所以m的取值范圍是,故選A。
13.解析:將代入結(jié)果為,∴時(shí),表示直線右側(cè)區(qū)域,反之,若表示直線右側(cè)區(qū)域,則,∴是充分不必要條件。
14.解析:∵,∴時(shí),,又時(shí),滿足上式,因此,。
15.解析:設(shè)正四面體的棱長為,連,取的中點(diǎn),連,∵為的中點(diǎn),∴∥,∴或其補(bǔ)角為與所成角,∵,,∴,∴,又∵,∴,∴與所成角的余弦值為。
16.解析:∵,∴,∵點(diǎn)為的準(zhǔn)線與軸的交點(diǎn),由向量的加法法則及拋物線的對稱性可知,點(diǎn)為拋物線上關(guān)于軸對稱的兩點(diǎn)且做出圖形如右圖,其中為點(diǎn)到準(zhǔn)線的距離,四邊形為菱形,∴,∴,∴,∴,∴,∴向量與的夾角為。
17.(10分)解析:(Ⅰ)由正弦定理得,,,…2分
∴,,………4分
(Ⅱ)∵,,∴,∴,………………………6分
又∵,∴,∴,………………………8分
∴!10分
18.解析:(Ⅰ)∵,∴;……………………理3文4分
(Ⅱ)∵三科會(huì)考不合格的概率均為,∴學(xué)生甲不能拿到高中畢業(yè)證的概率;……………………理6文8分
(Ⅲ)∵每科得A,B的概率分別為,∴學(xué)生甲被評為三好學(xué)生的概率為!12分
19.(12分)解析:(Ⅰ)∵,∴,
,,……………3分
(Ⅱ)∵,∴,
∴,
又,∴數(shù)列自第2項(xiàng)起是公比為的等比數(shù)列,………………………6分
∴,………………………8分
(Ⅲ)∵,∴,………………10分
∴!12分
20.解析:(Ⅰ)∵∥,,∴,∵底面,∴,∴平面,∴,又∵平面,∴,∴平面,∴!4分
(Ⅱ)∵平面,∴,,∴為二面角的平面角,………………………6分
,,∴,又∵平面,,∴,∴二面角的正切值的大小為!8分
(Ⅲ)過點(diǎn)做∥,交于點(diǎn),∵平面,∴為在平面內(nèi)的射影,∴為與平面所成的角,………………………10分
∵,∴,又∵∥,∴和與平面所成的角相等,∴與平面所成角的正切值為!12分
解法2:如圖建立空間直角坐標(biāo)系,(Ⅰ)∵,,∴點(diǎn)的坐標(biāo)分別是,,,∴,,設(shè),∵平面,∴,∴,取,∴,∴!4分
(Ⅱ)設(shè)二面角的大小為,∵平面的法向量是,平面的法向量是,∴,∴,∴二面角的正切值的大小為。………………………8分
(Ⅲ)設(shè)與平面所成角的大小為,∵平面的法向量是,,∴,∴,∴與平面所成角的正切值為。………………………12分
21.解析:(Ⅰ)設(shè)拋物線方程為,將代入方程得
所以拋物線方程為!2分
由題意知橢圓的焦點(diǎn)為、。
設(shè)橢圓的方程為,
∵過點(diǎn),∴,解得,,,
∴橢圓的方程為!5分
(Ⅱ)設(shè)的中點(diǎn)為,的方程為:,
以為直徑的圓交于兩點(diǎn),中點(diǎn)為。
設(shè),則
∵
………………………8分
∴
………………………10分
當(dāng)時(shí),,,
此時(shí),直線的方程為。………………………12分
22.(12分)解析:(Ⅰ)∵是偶函數(shù),∴,
又∵∴,,………………………2分
由得,,
∵時(shí),;時(shí),;時(shí),;∴時(shí),函數(shù)
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