0  899  907  913  917  923  925  929  935  937  943  949  953  955  959  965  967  973  977  979  983  985  989  991  993  994  995  997  998  999  1001  1003  1007  1009  1013  1015  1019  1025  1027  1033  1037  1039  1043  1049  1055  1057  1063  1067  1069  1075  1079  1085  1093  3002 

2009年龍巖市高中畢業(yè)班質(zhì)量檢查

理科綜合能力測(cè)試

YCY本試卷分為第Ⅰ卷(選擇題)和第Ⅱ卷(非選擇題)。第Ⅰ卷為必考題,第Ⅱ卷包括必考題和選考題兩部分。滿分300分,考試時(shí)間150分鐘。

注意事項(xiàng):

1.答題前,考生務(wù)必先將自己的姓名、準(zhǔn)考證號(hào)填寫(xiě)在答題卡上。

2.考生做答時(shí),請(qǐng)將答案答在答題卡上,在本試卷上答題無(wú)效;按照題號(hào)在各題的答題區(qū)域內(nèi)作答,超出答題區(qū)域書(shū)寫(xiě)的答案無(wú)效。

3.選擇題答案必須使用2B鉛筆填涂,如需改動(dòng)用橡皮擦干凈后,再選涂其它答案標(biāo)號(hào);非選擇題必須使用0.5毫米黑色字跡的簽字筆書(shū)寫(xiě),字體工整、字跡清楚。

4.做選考題時(shí),請(qǐng)考生按照題目要求作答。請(qǐng)按照題號(hào)在各題目的答題區(qū)域內(nèi)作答,超出答題區(qū)域書(shū)寫(xiě)的答案無(wú)效;在草稿紙、試題卷上答題無(wú)效。

5.保持卡面清潔,不要折疊、不要弄破、弄皺,不準(zhǔn)使用涂改液、刮紙刀。

可能用到的相對(duì)原子質(zhì)量:H-1  C-12  O-16  Na-23  Fe-56  S-32  I-127

第Ⅰ卷

本卷共18題,每題6分,共108分。在每小題列出的四個(gè)選項(xiàng)中,只有一項(xiàng)是最符合題目要求的。

一. 選擇題(本題共12小題。在每小題給出的四個(gè)選項(xiàng)中,只有一個(gè)選項(xiàng)符合題意)

1.下列探究實(shí)驗(yàn)或調(diào)查活動(dòng)中,計(jì)算所得數(shù)值與實(shí)際數(shù)值相比,可能偏大的是

A.探究土壤中小動(dòng)物類群豐富度時(shí),只用肉眼對(duì)小動(dòng)物進(jìn)行觀察和分類

B.探究生長(zhǎng)素類似物促進(jìn)插條生根時(shí),只統(tǒng)計(jì)長(zhǎng)度為2cm的根的數(shù)目

C.樣方法調(diào)查蒲公英種群密度時(shí),只在分布較稀疏的地塊取樣

D.調(diào)查人群中白化病的發(fā)病率時(shí),只以患者家族為調(diào)查對(duì)象

2.圖1表示在不同條件下,酶催化反應(yīng)情況。以下有關(guān)敘述不正確的是

 

 

 

 

圖1

A.與實(shí)線相比,圖1―①虛線能表示酶量增加后,其他條件不變時(shí),生成物量與反應(yīng)時(shí)間的關(guān)系

B.若圖1―①實(shí)線表示Fe3+對(duì)H2O2分解的催化效率,則虛線可表示過(guò)氧化氫酶的催化效率

C.圖1―②能用來(lái)表示反應(yīng)物濃度與反應(yīng)時(shí)間的關(guān)系

D.圖1―②能用來(lái)表示酶活性與pH的關(guān)系

3.下列不具有專一性(或特異性)的是

A.ATP與其參與的生理過(guò)程                         B.鳥(niǎo)嘌呤與其配對(duì)的堿基

C.tRNA與其轉(zhuǎn)運(yùn)的氨基酸                           D.細(xì)胞膜上的載體與其轉(zhuǎn)運(yùn)的離子

4.生長(zhǎng)素是人們最早發(fā)現(xiàn)的植物激素,下列有關(guān)生長(zhǎng)素說(shuō)法正確的是

A.生長(zhǎng)素在植物體各器官中均勻分布

B.植物的向光性是因?yàn)樵趩蝹?cè)光的作用下,向光側(cè)的生長(zhǎng)素比背光側(cè)多

C.植物的向光性不能體現(xiàn)生長(zhǎng)素作用的兩重性

D.在形成無(wú)子番茄過(guò)程中,生長(zhǎng)素改變了細(xì)胞的染色體數(shù)目

5.圖2表示不同概念之間的關(guān)系。下列各項(xiàng)中符合這種關(guān)系的是

A.Ⅰ共同進(jìn)化、Ⅱ生物多樣性、Ⅲ物種多樣性

B.Ⅰ生態(tài)系統(tǒng)的信息、Ⅱ行為信息、Ⅲ物理信息

C.Ⅰ競(jìng)爭(zhēng)、Ⅱ寄生、Ⅲ捕食

D.Ⅰ生態(tài)系統(tǒng)、Ⅱ種群、Ⅲ群落

6.下列關(guān)于環(huán)境、健康和發(fā)展的敘述中,不正確的是

A.光導(dǎo)纖維是以二氧化硅為主要原料制成的

B.硫酸工業(yè)尾氣未經(jīng)處理就直接排放,將直接導(dǎo)致“溫室效應(yīng)”

C.一些有效成分為碳酸鈣的補(bǔ)鈣劑需嚼爛服用,目的在于加快消化吸收

D.鐵質(zhì)器具表面刷漆或?qū)⑵渲糜诟稍锾幈4,均能有效減緩鐵的銹蝕

7.下列說(shuō)法正確的是

A.煤和天然氣都是可再生資源                      B.苯分子中存在C-C和C=C雙鍵

C.“酒越陳越香”與酯化反應(yīng)有關(guān)               D.糖類、蛋白質(zhì)都只含C、H、O元素

8.既能用濃硫酸又能用堿石灰干燥的是

A.Cl2                         B.SO2                                               C.CO                         D.NH3

9.設(shè)NA為阿伏加德羅常數(shù),下列敘述中正確的是

A.常溫下11.2L的HCl氣體含有HCl分子數(shù)為0.5NA個(gè)

B.32g O2和O3組成的混合物中總原子數(shù)為2NA個(gè)

C.0.1mol/L的氫氧化鈉溶液中含鈉離子數(shù)為0.1NA個(gè)

D.5.6g鐵與足量的Cl2反應(yīng)失去電子數(shù)為0.2NA個(gè)

10.下列反應(yīng)的離子方程式正確的是

A.氯化亞鐵溶液跟氯氣反應(yīng):2Fe2++Cl2 = 2Fe3++2Cl

B.向碳酸氫鈉溶液中滴加少量的稀硝酸:CO32+ 2H+ = CO2↑+ H2O

C.銅與稀硝酸反應(yīng):Cu+4H++2NO3=Cu2++2NO2↑+2H2O

D.碳酸氫銨溶液和足量氫氧化鈉溶液反應(yīng):NH4++OH=NH3?H2O

11.常溫時(shí),以下4種溶液pH最大的是

A.0.01mol ?L1氨水溶液

B.0.02mol ?L1氨水與0.02mol ?L1鹽酸溶液等體積混合液

C.0.03mol ?L1氨水與0.01mol ?L1鹽酸溶液等體積混合液

D.pH = 2的鹽酸與pH = 12的Ba(OH)2溶液等體積混合液

12.往FeCl3和BaCl2的混合溶液中通入SO2,溶液顏色由棕黃色變成淺綠色,同時(shí)有白色沉

淀產(chǎn)生。下列說(shuō)法正確的是

A.該實(shí)驗(yàn)表明FeCl3有還原性                       B.白色沉淀為BaSO3

C.該實(shí)驗(yàn)表明SO2有漂白性                          D.反應(yīng)后溶液酸性增強(qiáng)

二. 選擇題(本題共6小題。在每小題給出的四個(gè)選項(xiàng)中,有的只有一個(gè)選項(xiàng)正確,有的有多

個(gè)選項(xiàng)正確。全部選對(duì)的得6分,選對(duì)但不全的得3分,有選錯(cuò)或不答的得0分。)

13. 氣象衛(wèi)星是用來(lái)拍攝云層照片、觀測(cè)氣象資料和測(cè)量氣象數(shù)據(jù)的。我國(guó)先后自行成功研制

和發(fā)射了“風(fēng)云一號(hào)”和“風(fēng)云二號(hào)”兩顆氣象衛(wèi)星。“風(fēng)云一號(hào)”衛(wèi)星軌道與赤道平面

垂直并且通過(guò)兩極,每12小時(shí)繞地球一周,稱為“極地圓軌道”!帮L(fēng)云二號(hào)”氣象衛(wèi)星

的軌道是在赤道平面內(nèi)的“地球同步軌道”,則“風(fēng)云一號(hào)”衛(wèi)星比“風(fēng)云二號(hào)”衛(wèi)星

A.軌道半徑小            B.線速度小               C.角速度小        D.向心加速度小

14. 如圖3所示,在直角三角形ABC中,∠A=60°,∠B=90°,在A點(diǎn)放置一個(gè)點(diǎn)電荷,該

點(diǎn)電荷形成的電場(chǎng)在B點(diǎn)的場(chǎng)強(qiáng)方向由B指向A,B、C

兩點(diǎn)的場(chǎng)強(qiáng)大小分別為,電勢(shì)分別為。則

可以判定

A.                 B.

C.                  D.

15. 如圖4所示,兩束頻率不同的光束 A 和 B 分別沿半徑方向射入半圓形玻璃磚,出射光線

都是 OP方向。下面關(guān)于A 光和 B光的比較中,說(shuō)法正確的是

A.玻璃對(duì)A 光的折射率更大

B.真空中A光的波長(zhǎng)更長(zhǎng)

C.A光由玻璃射向空氣的全反射臨界角更大

D.玻璃中A光的傳播速度更大

16.國(guó)家大劇院外部呈橢球型。假設(shè)國(guó)家大劇院的屋頂為半球形,一保潔人員為執(zhí)行保潔任

務(wù),必須在半球形屋頂上向上緩慢爬行(如圖5所示),他在向上爬的過(guò)程中

A.屋頂對(duì)他的支持力不變

B.屋頂對(duì)他的支持力變大

C.屋頂對(duì)他的摩擦力不變

D.屋頂對(duì)他的摩擦力變大

17.如圖6所示,兩列簡(jiǎn)諧橫波a和b均沿x軸正方向傳播,波速為40m/s,下列說(shuō)法正確的是

 

 

 

 

 

A.a(chǎn)波的周期為0.2s、b波的周期為0.1s

B.對(duì)于b波,x軸上1m處的質(zhì)點(diǎn)經(jīng)過(guò)0.1s就傳到x=5m處

C.a(chǎn)、b兩列波相遇時(shí)發(fā)生干涉

D.x=8m處的質(zhì)點(diǎn)振動(dòng)總是加強(qiáng)的

18. 如圖7中圖甲所示,固定在水平桌面上的光滑金屬框架cdeg處于方向豎直向下的勻強(qiáng)磁

場(chǎng)中,金屬桿ab與金屬框架接觸良好。在兩根導(dǎo)軌的端點(diǎn)d、e之間連接一個(gè)電阻R,其

他部分電阻忽略不計(jì),F(xiàn)用一水平向

右的外力F作用在金屬桿ab上,使金

屬桿由靜止開(kāi)始向右在框架上滑動(dòng),

運(yùn)動(dòng)過(guò)程中桿ab始終垂直于框架。圖

乙是金屬桿運(yùn)動(dòng)的v―t圖像,則圖8

中可以表示外力F隨時(shí)間t變化關(guān)系的

圖像是

 

 

 

 

 

圖8

第Ⅱ卷

本卷共192分,包括必考題和選考題兩部分。第19~27和32題為必考題;第28~31為選考題,考生根據(jù)要求選擇作答。

【必考部分】(共157分)

19.(18分)(1)在“用單擺測(cè)定重力加速度”的實(shí)驗(yàn)中:

①甲同學(xué)分別選用三種材料不同而直徑都為2cm的實(shí)心球、長(zhǎng)度不同的細(xì)棉線組成單擺,完成了四組實(shí)驗(yàn)。各組實(shí)驗(yàn)的器材和部分測(cè)量數(shù)據(jù)如下表。其中最合理的實(shí)驗(yàn)是第      組。

 

組別

擺球材料

擺長(zhǎng)L/m

最大擺角

全振動(dòng)次數(shù)N/次

1

0.30

50

2

1.00

1

3

1.00

50

4

1.00

10

 

    ②乙同學(xué)選擇了合理的實(shí)驗(yàn)裝置后,測(cè)出幾組不同擺長(zhǎng)L和周

期T的數(shù)值,畫(huà)出如圖9的T2―L圖象,并算出圖線的斜率為k,

則當(dāng)?shù)氐闹亓铀俣萭=      (用符號(hào)表示)。

③丙、丁兩同學(xué)合作測(cè)量重力加速度,也測(cè)出幾組不同擺長(zhǎng)L和周

期T的數(shù)值。丙用T2―L圖像法處理求得重力加速度為g;丁用公式

處理求得重力加速度為g,實(shí)驗(yàn)后他們發(fā)現(xiàn)測(cè)擺長(zhǎng)時(shí)

忘了加上擺球的半徑,則丙、丁兩同學(xué)計(jì)算出的重力加速度數(shù)值關(guān)系為g      g(填“>”“<”“=”) 。

(2)一節(jié)電動(dòng)勢(shì)約為9V、內(nèi)阻約為2Ω的電池,允許通過(guò)的最大電流是500mA。為了測(cè)定該電池的電動(dòng)勢(shì)和內(nèi)電阻,選用了總阻值為50Ω的滑動(dòng)變阻器以及電流表和電壓表等,連成了如圖10所示的電路。

①為了防止誤將滑動(dòng)變阻器電阻調(diào)為零而損壞器材,需要在電路中接入一個(gè)保護(hù)電阻R,最適合的電阻是(   )

A.10Ω,5W                        B.10Ω,0.5W

C.20Ω,5W                        D.20Ω,0.5W

②由于電路中有一條導(dǎo)線發(fā)生了斷路,閉合電鍵K后發(fā)現(xiàn)電壓表、電流表均無(wú)示數(shù),則出現(xiàn)斷路的導(dǎo)線是       (填導(dǎo)線上的序號(hào))。

③實(shí)驗(yàn)中,要使電壓表的示數(shù)變大,滑動(dòng)變阻器的滑片應(yīng)向     端移動(dòng)。(填“E”或“F”)

20. (15分)2008年北京奧運(yùn)會(huì)的開(kāi)幕式上,用焰火打出奧運(yùn)五環(huán)圖案、2008等中英文字樣,這其中的關(guān)鍵技術(shù)就是焰火的空中定向、定位與藝術(shù)造型技術(shù)。假設(shè)有一質(zhì)量5kg的焰火彈,要豎直發(fā)射到距炮筒出口150m的最高點(diǎn)時(shí)恰好點(diǎn)火,焰火彈在上升過(guò)程中受到的空氣阻力恒為自身重力的0.20倍。(g取10m/s2)請(qǐng)問(wèn):

(1)設(shè)計(jì)師設(shè)計(jì)的焰火彈離開(kāi)炮筒時(shí)的速度多大?

 

(2)從離開(kāi)炮筒口到最高點(diǎn)點(diǎn)火,其控制時(shí)間應(yīng)設(shè)定多長(zhǎng)?

 

21.(19分)如圖11所示,在x軸上方有垂直于xy平面向外的勻強(qiáng)磁場(chǎng),磁感應(yīng)強(qiáng)度為B;在x軸下方有平行于x軸,方向沿x軸負(fù)方向的勻強(qiáng)電場(chǎng),場(chǎng)強(qiáng)為E。一質(zhì)量為m,電量為e的質(zhì)子從y軸上的M點(diǎn)以的速度平行x軸正方向進(jìn)入磁場(chǎng),通過(guò)磁場(chǎng)后垂直于x軸進(jìn)入電場(chǎng),從y軸的P點(diǎn)離開(kāi)電場(chǎng)。(質(zhì)子重力不計(jì))求:

(1)M點(diǎn)與O點(diǎn)的距離;

 

(2)粒子從M點(diǎn)運(yùn)動(dòng)到P點(diǎn)的時(shí)間;

 

(3)粒子到達(dá)P點(diǎn)時(shí)的速度大小。

 

22.(20分)如圖12所示,輕彈簧左端固定在豎直墻上,右端點(diǎn)在O位置。質(zhì)量為m的物塊A(可視為質(zhì)點(diǎn))以初速度v0從距O點(diǎn)右方s0的P點(diǎn)處向左運(yùn)動(dòng),與彈簧接觸后壓縮彈簧,將彈簧右端壓到O´點(diǎn)位置后,A又被彈簧彈回。A離開(kāi)彈簧后,恰好回到P點(diǎn)。物塊A與水平面間的動(dòng)摩擦因數(shù)為μ。求:

(1)物塊A從P點(diǎn)出發(fā)又回到P點(diǎn)的過(guò)程,克服摩擦力所做的

功;

 

(2)O點(diǎn)和O´點(diǎn)間的距離s1;

 

(3)若將另一個(gè)與A完全相同的物塊B(可視為質(zhì)點(diǎn))與彈簧右端拴接,將A放在B右邊,向左壓A、B,使彈簧右端壓縮到O´點(diǎn)位置,然后從靜止釋放,A、B共同滑行一段距離后分離。分離后物塊A向右滑行的最大距離s2是多少?

 

23.(14分)短周期元素A、B、C、D在周期表中位置如圖13所示,其中元素D原子最外層有3個(gè)電子。

(1)C的單質(zhì)能使?jié)駶?rùn)的有色布條褪色,使布條褪色的物質(zhì)化學(xué)式是             

(2)元素A的某種氧化物和氧氣在KOH溶液中可構(gòu)成燃料電池,該電池工作時(shí)正極的電極反應(yīng)式為         

(3)D的氧化物與NaOH溶液反應(yīng)的化學(xué)方程式是                     。

(4)B的單質(zhì)與氫氣在1L密閉容器中進(jìn)行反應(yīng),進(jìn)行到2min時(shí),氫氣物質(zhì)的量減少了0.15mol。該反應(yīng)在2min內(nèi)單質(zhì)B的平均反應(yīng)速率是                ;

(5)B的氫化物與C的氫化物反應(yīng)產(chǎn)生白煙,此反應(yīng)產(chǎn)物的水溶液中各種離子物質(zhì)的量濃度的大小順序是                         ;

(6)D單質(zhì)的某種反應(yīng)可用于焊接鋼軌,該反應(yīng)的化學(xué)方程式是                 。

24.(17分)氫氧化鎂用于制藥工業(yè),還是重要的綠色阻燃劑。

I、治療胃酸過(guò)多藥物Stmoache的有效成分為Mg(OH)2。

(1)該藥物治療胃酸(主要成分為鹽酸)過(guò)多癥時(shí)反應(yīng)的離子方程式:_____________。

Ⅱ、已知:Mg (s)+2H2O(g)=Mg(OH)2(s)+H2(g)           △H1=-441kJ?mol1

H2O(g)=H2(g)+O2(g)                                     △H2=+242kJ?mol1

Mg(s)+O2(g)=MgO(s)                             △H3=-602kJ?mol1

(2)氫氧化鎂分解的熱化學(xué)方程式是_______________________________________。

(3)氫氧化鎂可以作為阻燃劑的原因____________________。(寫(xiě)一條即可)

Ⅲ、某工廠用六水合氯化鎂和粗石灰制取的氫氧化鎂含有少量氫氧化鐵雜質(zhì),通過(guò)如下流程進(jìn)行提純精制,獲得阻燃劑氫氧化鎂。

 

 

 

 

 

(4)步驟②中分離操作的名稱是_____________。

(5)步驟①中的反應(yīng)如下:6Fe(OH)3 +S2O42+2OH =6Fe(OH)2 +2SO42+4H2O。

每消耗0.1mol保險(xiǎn)粉(Na2S2O4)時(shí),轉(zhuǎn)移電子的數(shù)目是        NA

(6)已知EDTA只能與溶液中的Fe2+反應(yīng)生成易溶于水的物質(zhì),不與Mg(0H)2反應(yīng)。雖然Fe(OH)2難溶于水,但步驟②中隨著EDTA的加入,最終能夠?qū)e(OH)2除去并獲得純度高的Mg(OH)2。請(qǐng)從沉淀溶解平衡的角度加以解釋。

答:_____________________________________________________________________。

Ⅳ、為研究不同分離提純條件下所制得阻燃劑的純度從而確定最佳提純條件,某研究小組各取等質(zhì)量的下列4組條件下制得的阻燃劑進(jìn)行含鐵量的測(cè)定,結(jié)果如下:

 

精制阻燃劑的條件

阻燃劑鐵含量

序號(hào)

提純體系溫度T/℃

加入EDTA質(zhì)量(g)

加入保險(xiǎn)粉質(zhì)量(g)

W(Fe)/(10-4g)

1

40

0.05

0.05

7.63

2

40

0.05

0.10

6.83

3

60

0.05

0.10

6.83

4

60

0.10

0.10

6.51

 

(7)若不考慮其它條件,根據(jù)上表數(shù)據(jù),制取高純度阻燃劑最佳條件是______(填字母)

①40℃           ②60℃           ③EDTA質(zhì)量為0.05g         ④EDTA質(zhì)量為0.10g

⑤保險(xiǎn)粉質(zhì)量為0.05g         ⑥保險(xiǎn)粉質(zhì)量為0.10g

A.①③⑤                   B.②④⑥                   C.①④⑥                   D.②③⑤

25.(14分)測(cè)定平衡常數(shù)對(duì)定量認(rèn)識(shí)化學(xué)反應(yīng)具有重要意義。已知:碘單質(zhì)能與I反應(yīng)成I3,并在溶液中建立如下平衡:I2 +II3 。通過(guò)測(cè)平衡體系中c(I2)、c(I)和c(I3),就可求得該反應(yīng)的平衡常數(shù)。

I、某同學(xué)為測(cè)定上述平衡體系中c(I2),采用如下方法:取V1 mL平衡混合溶液,用c mol?L1的Na2S2O3溶液進(jìn)行滴定(反應(yīng)為I2+2Na2S2O3=2NaI+Na2S4O6),消耗V2 mL的Na2S2O3溶液。根據(jù)V1、V2和c可求得c(I2)。

(1)上述滴定時(shí),可采用___________做指示劑,滴定終點(diǎn)的現(xiàn)象是________。

(2)下列對(duì)該同學(xué)設(shè)計(jì)方案的分析,正確的是____________(填字母)。

A.方案可行。能準(zhǔn)確測(cè)定溶液中的c(I2)

B.不可行。因?yàn)镮能與Na2S2O3發(fā)生反應(yīng)

C.不可行。只能測(cè)得溶液中c(I2)與c(I3)之和

Ⅱ、科研實(shí)踐中可采用下述方法來(lái)測(cè)定該反應(yīng)的平衡常數(shù)(室溫條件下進(jìn)行):

 

一定質(zhì)量I2

(完全溶解)

 

 

 

 

 

已知:①I(mǎi)和I3不溶于CCl4;②一定溫度下碘單質(zhì)在四氯化碳和水混合液體中,碘單質(zhì)

的濃度比值即是一個(gè)常數(shù)(用Kd表示,稱為分配系數(shù)),且室溫條件下Kd=85。

回答下列問(wèn)題:

(3)操作Ⅰ使用的玻璃儀器中,除燒杯、玻璃棒外,還需要的儀器是__________(填名稱)。

(4)下層液體中碘單質(zhì)的物質(zhì)的量濃度是___________________________________。

(5)實(shí)驗(yàn)測(cè)得上層溶液中c(I3)=0.049 mol?L1,結(jié)合上述有關(guān)數(shù)據(jù),計(jì)算室溫條件下反應(yīng)I2 +II3的平衡常數(shù)K=____________________(用具體數(shù)據(jù)列出計(jì)算式即可)。

26.(25分)Ⅰ.圖14表示在20℃條件下,A、B兩種植物光合速度隨光照強(qiáng)度改變的變化曲線。請(qǐng)回答下列問(wèn)題:

(1)在較長(zhǎng)時(shí)間連續(xù)陰雨的環(huán)境中,A、B植物相比,受到影響較大的是     植物。

(2)當(dāng)光照強(qiáng)度為a時(shí),比較A、B植物的有機(jī)物積累速率MA 、MB和有機(jī)物合成速率NA 、NB 的大小,結(jié)果應(yīng)分別為MA     MB 、NA     NB(填“>”、“<”或“=”)。此時(shí),A植物葉綠體中ADP的移動(dòng)方向是從

           部位移動(dòng)。

(3)當(dāng)光照強(qiáng)度大于16千勒克司時(shí),受          等環(huán)境因素的影響,A植物的光合速度不再增大。

(4)為探究光合作用釋放的氧氣是來(lái)自水還是二氧化碳,某同學(xué)用18O標(biāo)記了光合作用的原料H2O,經(jīng)分析,釋放的氧氣含有18O。由此他得出結(jié)論:光合作用釋放的氧氣來(lái)自水。該實(shí)驗(yàn)不夠嚴(yán)密,還應(yīng)增設(shè)一個(gè)實(shí)驗(yàn)組,你認(rèn)為應(yīng)該怎么做?

                                                                           。

Ⅱ.中國(guó)第25次南極科考隊(duì)在南極進(jìn)行了為期5個(gè)月的科學(xué)考察。在南極,科考隊(duì)員的體溫始終維持在37℃左右。請(qǐng)回答:

(1)體溫恒定對(duì)于人體至關(guān)重要,因?yàn)轶w溫的異常會(huì)直接影響      的活性,進(jìn)而影響正常的生命活動(dòng)。

(2)在南極寒冷氣候下,人體體溫低于正常體溫時(shí),體溫感受器產(chǎn)生的興奮傳至體溫調(diào)節(jié)中樞――         ,進(jìn)行分析綜合后,通過(guò)神經(jīng)――體液發(fā)送信息,使皮膚汗腺分泌減少,毛細(xì)血管       ,從而減少散熱;同時(shí),       等器官產(chǎn)熱增多,使體溫回升。在這一調(diào)節(jié)過(guò)程中,體內(nèi)           等激素濃度升高。

27.(15分)小鼠是遺傳學(xué)常用的實(shí)驗(yàn)材料,性別決定方式為XY型。小鼠的EPPK癥是以其掌跖表皮過(guò)度角化和松懈為主要特征的一種皮膚遺傳病,已知該癥由核內(nèi)顯性基因A控制。請(qǐng)回答:

(1)一只雌性小鼠患有EPPK癥,該小鼠的雙親及周圍其他個(gè)體的皮膚都正常,則該變異的來(lái)源最可能是        。

(2)讓(1)中的該患病小鼠與正常雄鼠雜交,得到足夠多的F1個(gè)體,統(tǒng)計(jì)發(fā)現(xiàn)F1表現(xiàn)型及比例為EPPK癥雌鼠∶EPPK癥雄鼠∶正常雌鼠∶正常雄鼠=1∶1∶1∶1。此結(jié)果說(shuō)明

(1)中的EPPK癥雌鼠為        (純合子、雜合子),        (可以確定、無(wú)法確定)該基因位于常染色體上。

(3)若已確定控制EPPK癥的基因位于常染色體上,小鼠的血友病是伴X染色體的隱性遺傳。ㄓ肂、b表示),F(xiàn)有EPPK癥非血友病雄鼠和正常皮膚血友病雌鼠若干只,為了驗(yàn)證這兩對(duì)相對(duì)性狀遵循自由組合定律,應(yīng)選用的雜交親本的基因型是          ,產(chǎn)生的后代表現(xiàn)型的比例為        ,后代中表現(xiàn)型有      種與親本的類型不同。

【選考部分】(共35分)

第Ⅱ卷選考部分共5題,共35分。其中第28、29題為物理題,第30、31題為化學(xué)題?忌鷱膬傻牢锢、兩道化學(xué)題中各任選一題作答,若28、29題都作答,則按第28題計(jì)分,若第30、31題都作答,則按第30題計(jì)分;第32題為生物題,是必答題。請(qǐng)將答案都填寫(xiě)在答題卡選答區(qū)域的指定位置上。

28. [物理――選修3―3](本題共有兩小題,每小題6分,共12分。每小題只有一個(gè)選項(xiàng)符合題意。)

(1)下列說(shuō)法正確的是          (填選項(xiàng)前編號(hào))。

①物體的溫度升高時(shí),其內(nèi)部每個(gè)分子的熱運(yùn)動(dòng)速率都一定增大

②布朗運(yùn)動(dòng)指的是液體分子的無(wú)規(guī)則運(yùn)動(dòng)

③第二類永動(dòng)機(jī)雖不違背能量守恒定律,但仍不可能制成

④外界對(duì)氣體做正功,氣體的內(nèi)能一定增加

(2)如圖15所示,兩端開(kāi)口的U形均勻玻璃管開(kāi)口向上豎直放置,由兩段水銀封閉了一段空氣柱,穩(wěn)定后,空氣柱的長(zhǎng)度L=12cm,a、b兩水銀面的高度差h=19cm,F(xiàn)從U形管左端再注入一段長(zhǎng)為19cm的水銀柱,并保持空氣柱溫度不變,再次穩(wěn)定后,空氣柱的長(zhǎng)度為(已知外界大氣壓相當(dāng)于76cm高水銀柱產(chǎn)生的壓強(qiáng),U形管內(nèi)水銀不會(huì)溢出)            。(填選項(xiàng)前編號(hào))

①8cm       ②10cm      、12cm      ④14.4cm

29. [物理――選修3―5](本題共有兩小題,每小題6分,共12分。每小題只有一個(gè)選項(xiàng)符合題意。)

(1)我國(guó)自行研制了可控?zé)岷朔磻?yīng)實(shí)驗(yàn)裝置“超導(dǎo)托卡馬克”(英文名稱:EAST,俗稱“人造太陽(yáng)”)。設(shè)可控?zé)岷藢?shí)驗(yàn)反應(yīng)前氘核()的質(zhì)量為m1,氚核()的質(zhì)量為m2,反應(yīng)后氦核(e)的質(zhì)量為m3,中子()的質(zhì)量為m4。已知光速為c。則下列說(shuō)法中正確的是

         (填選項(xiàng)前編號(hào)) 。

①這種裝置中發(fā)生核反應(yīng)的方程式是

②由核反應(yīng)過(guò)程質(zhì)量守恒可知m1+m2= m3+m4

③核反應(yīng)釋放的能量等于 (m1+m2 ? m3 ? m4 )c2

④這種裝置與我國(guó)大亞灣核電站所使用核裝置的核反應(yīng)原理相同

(2)小車靜止在光滑水平面上,站在車上的人練習(xí)打靶(人相對(duì)于小車靜止不動(dòng)),靶裝在車上的另一端,如圖16所示,已知車、人、槍和靶的總質(zhì)量為M(不含子彈),子彈的質(zhì)量為m,若子彈離開(kāi)槍口的水平速度大小為v0(空氣阻力不計(jì)),子彈打入靶中且留在靶里,則子彈射入靶后,小車獲得的速度大小為         。(填選項(xiàng)前的編號(hào))

①0         ②          ③            ④

30.[化學(xué)―物質(zhì)結(jié)構(gòu)與性質(zhì)] (13分)

X、Y、Z三種元素,原子序數(shù)依次減小。X是第四周期主族元素,其部分電離能如圖17所示;X、Y元素具有相同的最高正化合價(jià);Z原子價(jià)電子排布式nsnnpn;卮鹣铝袉(wèn)題:

(1)X原子的電子排布式為_(kāi)__________。

(2)電負(fù)性:X ______Y(填“>”、“=”或“<”)。

(3)元素Z的一種氫化物(化學(xué)式為Z2H4)是重要的

化工原料。有關(guān)Z2H4分子的說(shuō)法正確的是______(填字母)。

A.分子中含有氫鍵

B.屬于非極性分子

C.含有4個(gè)σ鍵和1個(gè)π鍵

D.Z的原子與氫原子形成的化學(xué)鍵可以旋轉(zhuǎn)

(4)X的氧化物與鈦(Ti)的氧化物相互作用,能形成鈦酸鹽,

其晶體結(jié)構(gòu)示意圖如圖18所示(X、Ti和O三種元素對(duì)應(yīng)的離子

分別位于立方體的體心、頂點(diǎn)和面心)。該晶體中,鈦離子和周圍

_________(填數(shù)字)個(gè)氧離子相緊鄰。

(5)NH4Cl晶體中含有多種化學(xué)鍵,其中一定不含有的化學(xué)鍵是_____(填字母)。

A.離子鍵            B.非極性鍵               C.配位鍵           D.金屬鍵

31.[化學(xué)――有機(jī)化學(xué)基礎(chǔ)](13分)

龍膽酸甲酯是制取抗心律失常藥物――氟卡尼的中間體。

I、已知,龍膽酸甲酯結(jié)構(gòu)如圖19所示。

(1)下列有關(guān)龍膽酸甲酯的描述,不正確的是       (填字母)。

A.能與氯化鐵溶液顯色

B.分子中含有羧基、羥基等官能團(tuán)

C.能與溴水反應(yīng)

D.能與碳酸鈉溶液反應(yīng)產(chǎn)生二氧化碳

II、已知:RCH2CH(OH)CH3          RCH=CHCH3和RCH2CH=CH2

X及其他幾種有機(jī)物存在如下轉(zhuǎn)化關(guān)系,且A和B互為同分異構(gòu)體:

 

文本框: 銀氨溶液
 

 

 

 

 

 

回答以下問(wèn)題:

(2)龍膽酸甲酯與足量氫氧化鈉溶液反應(yīng)的化學(xué)方程式是                     。

(3)上述轉(zhuǎn)化關(guān)系中沒(méi)有涉及的反應(yīng)類型是             (填代號(hào))。

①取代反應(yīng)  ②加成反應(yīng)  ③消去反應(yīng)  ④氧化反應(yīng)  ⑤還原反應(yīng)  ⑥加聚反應(yīng)

(4)符合上述轉(zhuǎn)化關(guān)系的X的結(jié)構(gòu)簡(jiǎn)式是                               。

 

32.(10分)我國(guó)科學(xué)家通過(guò)基因工程成功培育出能抗棉鈴蟲(chóng)的棉花植株――抗蟲(chóng)棉。請(qǐng)回答:

(1)生產(chǎn)轉(zhuǎn)基因抗蟲(chóng)棉的核心步驟是_______,該過(guò)程用到的工具酶有______和_______。

(2)含有Bt毒蛋白基因的重組Ti質(zhì)粒導(dǎo)入棉花細(xì)胞培養(yǎng)成棉花植株后,是否翻譯出Bt毒蛋白,檢測(cè)的方法是進(jìn)行          雜交。

(3)為了克服季節(jié)、氣候、地域限制,快速制種,便于大面積推廣種植,可將抗蟲(chóng)棉植株組織培養(yǎng)得到的胚狀體、不定芽等,制成_______。

 

 

 

 

2009年龍巖市高中畢業(yè)班質(zhì)量檢查

試題詳情

2009年河南省普通高中畢業(yè)班教學(xué)質(zhì)量調(diào)研考試

英語(yǔ)  2009年3月14考試(聽(tīng)力省略)

第I卷

21When I got____call from Mrs.Leary saying that I was recommened as ______babysister,Iaccepted without hesitation.

A.the; the  B.a;the;  C.a;a  D.the;  a

22---I'm here just looking for some antiques at this sale.

----Have you found____?So many at hand!

A.anything  B.something  C.evrything  D.nothing

23It was a tough____to make,but I was determined to leave my job.

A.decision  B.chance  C.excuse  D.move

24----Why didn't you come to Mike's birthday party yesterday?

------Well,I________,but I forgot it.

A.should  B.must  C.should have  D.must have

25----They're announcing your flight.You'd better get on board the plane.

-----_______you______me?

A.Are,rushing  B.Have,rushed  C.Will ,rush  D.Do,rush

26---Spacecraft "Discovery"has failed in the course of launch.

---_____?They have  been preparing for the test

A.How come B.Who says  C.What for  D.Why not

27Tom did well in the last exam,and much to my joy,Mary did____than Tom.

A.no better  B.no worse  C.not better  D.not worse

28Mr Blaire,under______direction the sales department achieved the goal,quitted the job last week.

A.him  B.whose  C.whom  D.his

29---What's happened to Mr.Jones?

-----I'm not quite sure.He_____arround here for a long time.

A.hasn't seen  B.didn't see  C.wasn't seen  D.hasn't been seen

30I can't go home and have a good rest.I'm already_____schedule.

A.behind  B.against  C.within  D.beyond

31_____a car,he usually takes the bus to his office,which takes him almost an hour.

A.He doesn't have  B.Not have  C.Not having  D.He didn't have

32.The Jojnsons have moved to a different house____their children can attend a better school.

A.even though  B.so that  C.as if  D.in case

33.I wanted to say something,but her face quite___me____.

A.threw;off  B.took;off   C.set;off  D.put;off

34.I wanted to say something ,but her face quite____me_____.

A.on and on  B.up and down  C.over and over  D.by and by

35.---Go for hiking this Saturday,OK?

-----______.I like getting close to nature.

A.I couldn't agree more  B.I believe not  C.I'm afraid not  D.I don't think so

第二節(jié)  完形填空

 

The art of living is to know when to hold fast and when to let go.When know that this is(36),but all too often we recognize this truth(37)in our backward glance when we remember what it was and then suddenly(38)that is no more.

A recent(39)re-taught me this truth.I was hospitalized(_40)a serious heart attack and had been in intensive(_41)for several days.It was not a pleasant p[lace.

One morning,I had to have some additional(42),so I had to be wheeled across the countyard on a gurney(n.輪床).

(43)we got out from our unit,the sunlight hit me.Just the(44)of the sun.And yet how beautiful it was---how warming,how sparking,how brilliant!I (45)arround to see whether anyone else loved the sun's golden glow,but everyone was(46),most with eyes fixed on the ground.At that moment,I came to realize(47)gifts are precious----but we are too(48)about them.

      Hold fast to life,but not so fast,or you cannot(49).This is the second side of life's(50),the opposite pole of its paradox(悖論):we  must (51)our losses,and learn how to let go.

      This is not an easy(52)to learn,especially when we are young and think that the world is ours to command,and that(53)we desire with the full force of our passionate being can,and,will,be ours.But then life(54),keeping us faced with realities,and(55)but surely this truth dawns upon us.

36A.easy  B.clear C.true  D.good

37A.only  B.also  C.well  D.even

38A.notice  B.realize  C.worry  D.concern

39A.report  B.story  C.accident  D.experience

40A.during B.since  C.after  D.until

41A.care  B.charge  C.control  D.need

42A.doctors  B.medicine  C.instructions  D.tests

43A.Before  B.Till  C.As  D.Whille

44A.warmth  B.light  C.colors  D.image

45A.looked  B.turned  C.walked  D.ran

46A.watching  B.hurrying  C.working  D.sitting

47A.disease's  B.art's  C.health's  D.life's

48A.honest  B.curious  C.careless  D.anxious

49A.hold on  B.take over  C.give in  D.let go

50A.coin  B.note  C.bill  D.check

51A.accept  B.admire  C.remember  D.forgive

52.A.skill  B.failure  C.lesson  D.task

53A.whatever  B.whichever  C.however  D.whoever

54A.comes up  B.goes off  C.dies away  D.moves along

55 A.quickly  B.firmly  C.slowly  D.suddenly

第三部分閱讀理解

A

One day,an expert in time management was speaking to a group of students and ,to drive home a point,used an illustration those students will never forget.

Standing before the group of overachievers(成績(jī)超過(guò)預(yù)料的學(xué)生),he said,"Ok,time for a quiz."He pulled out out a one-gallon,wide -mouth jar and set it on the table in front of him.He also produced about a dozen fist-sized rorocks and carefully placed them,one at a time,into the jar.When no more rocks would fit inside,he asked,"Is this jar full?"

Everyone in the class yelled,"Yes"The expert reached under the table and pulled out a bucket of gravel.He dumped some gravel in and shook the jar,causing pieces of gravel to work themselves down into the spaces between the big rocks.He then asked again,"Is this jar full?"

"Probably not."one of them answered."Good."He replied.He reached under the table and brought out a bucket of sand.He started dumping the sand in the jar and it went into all of the spaces left between the rocks and the gravel.Onece more he asked the question,"Is this jar full?”

“No!"the class shouted."Good."He replied.He grabbed a pitcher of water and began to pour it in until the jar was filled to the brim.Then he looked at the class and asked,"What is the point of this illustration?"One eager student raised his hand and said,’“No matter how full your schedule is,if you try really hard you can always fit some more things in it!"

"_______,"the expert replied.“The truth this illustrtion teaches us if you don't put the big rocks in first ,you'll never get them in at all.What are the "big rocks"in your life?Time with your loved ones,your education,your dreams,a worthy cause,or teaching others?Remember to put these big rocks in first or you'llnever get them in at all."

56Which group of words means containers?

A.jar,gravel,bucket  B.jar,illustration,gravel

C.jar,bucket,pitcher    D.jar,brim,pitcher

57What replies would the expert probably make in the last paragraph

A.I beg you pardon  B.Good idea 

C.That's not the point  D.You got it

58Choose the order that the expert put things in the jar.

A.rocks--->sand---->gravel---->water

B.rocks--->gravel--->sand---->water

C.gravel---->water----.>sand---->rocks

D.gravel--->sand--->water--->rocks

59What's the expert's conclusion?

A.We  must  think of  all kinds of ways to solve our problems

BWe must try really hard to fit more small things in our life

C.We must know what big rocks are in our life and then put them in first

D.We must know things like gravel,sand and water are not important at all

B

For many students in Beijing,Mr.Obama symbolizes all that is possible in the United States.He's a popular winner here,seen as a self-made man who has made it to the top.

"I think he is very charming,and a president who can create a new era(時(shí)代),"said ZhangWei,a university student."I like him very much and most of my friends do too."

Ni Weibo,another university student,agrees."Sino-U.S. Relations still need more cooperation,"she said."I think he will help take it to a new era."

China's President Hu Jintao congratulated Mr. Obama within hours of his victory,saying he hoped bilateral ties could be made stronger.

Political analysts(分析家)here say China will be looking for the incoming president to avoid contentious issues such as Taiwan's independence,human rights and Tibet.

Instead,they say Beijing would like Mr Obama to focus on solving the global economic crisis(危機(jī)),and to help China's slowing economy by opening up U.S. Markets.

But trade relations might be a sticking point,says Renmin University's Professor of International Studies,Shi Yinhong.

He warns,"There is a possibility that President Obama will take some protectionist measures which China will not  accept,then trade disputes could develop to a degree that we have not seen ever before."

Despite making the headlines,Mr.Obama faces some tough challenges in managing the U.S. Relationship with China.

China is now a stronger and more confident country than the China his predecessors(前任)dealt with.And in this time of economic uncertainty,analysts say it's a country with wich Mr.Obama will want to maintain a good relationship.

60Many students in Beijing  expect that Mr.Obama  can________.

A.made everything possible  B.further strengthen Sino-U.S.relations

C.become a self-made man  D.try to help China into a new era

61According to some analysts,which of the following is what China would like Mr.Obama to do?

A.Facing some tough challenges  B.Taking some protectionist measures

C.Making Sino-U.S.bilateral ties stronger 

D.Opening up markets to speed China's economy

62The underlined word "dispute"means"______"

A.serious disagreemen  B.severe measures

C.tough crisis  D.confusing issues

63As mentioned in the text,Mr. Obama will want to maintain a good relationship with China because________.

A.China is now a stronger and more confident country

B.he has tough challenges in managing the relationship with China

C.he wants to avoid issues like Taiwan's independence,human rights and Tibet

D.Mr.Hu Jintao congratulated Mr.Obama within hours of his victory

C

It used to be that shopping was a fairly simple activity---you went to the supermarket,picked up what you need,paid for it and left.But in recent years it's become a lot more complicated.Supermakets in the UK now sell much more than food :you can get your insurance there ,pay bills and a variety of other services.In many ways they've become a one-stop shop for lots of life's daily chores.

You can also get "rewards"----join up and get a "loyalty card"and every time you shop you'll get points and discounts.And just when you thought supermakets couldn't offer anything else,they turned into mini-banks,offering you cash when you shop .Go into any UK supermarket,pay for your shopping,and you're more than likely to be asked if you want "any cashback with that?”

This is only offered if you pay by debit card(簽證卡).Effectively,if you buy ζ30 worth of shopping,you can pay ζ50 with your debit card and the supermarket will give you your shopping plus,ζ20 in cash from the till(收款機(jī))。

Originally introduced by the supermaket gaint Tesco,it eases busy shoppers' lives by cutting out an extra visit to the bank.Of curse, they didn't just introduce this for the customer's benefit---shops also benifit by having less cash in-house,and by paying less in fess for taking this cash to their local bank.

In recent years the phrase "cashback!"has also  been observed as an exclamation of joy or satisfaction,as in:"It's three drinks for the price of two in the pub tonight.Cashback!"

64Supermakets in the UK now are different from what it used be because_______

A.they will ask shoppers to pay only by cashback

B.they don't sell food and other daily necessitites

C.they have made shopping much more complicated

D.they provide a veriety of other services besides shopping

65.The cash you get when you shop in supermakets comes from the______.

A.points and discounts  B.built-in mini-banks

C.supermaket giant Tesco  D.extra visits to the bank

66Who will benefit from"Cashback!"?

A.Only busy shoppers  B.Only supermakets

C.The local banks  D.Both shoppers and shops

67What may be the best title for the text?

A.UK Supermarkets  B.Cashback!  C.One-stop Shops  D.The Best Services

D

★Apsley House is the London town house of the Dukes of Wellington.Inside you will find palatial State Rooms including the sumptuous Waterloo Gallery hung with rare Old Masters.The house contains an unrivalled collection of porcelain,silver and Wellington memorabilia.

Admission:Adult ζ5.50.

Opening Times:Oct & from 21 Mar Wed-Sun 11.00---17.00.

          1 Nov--31 Mar Wed--Sun 11.00---16.00.

          Closed Mon&Tue

Visit Time:1 hour.

Telephone 020 7499 5676

Please see website for more information.

★Benjamin Franklin House,The world's only remaining Franklin home and listed Georgian building,is just steps from Charing Cross.The Historical Experience presents the exitement of Franklin's London years through live Audio-visual performance.

Admission:Adult ζ7.00.

Tour Times:Wed-Sun 12.00,13.00,14.00,15.15,16.15

          Closed Mon and Tue

Visit Time:1 hour.

Telephone:020 7839 2006.

Please see website for more information.

★Visit Kensington bPalace and immerse yourself in centuries of royal style.Explore the elegant State Apartments,including the magnificent King's Staircase and the Victorian Rooms,where a young Victoria awoke to the news that she was to be queen.

Take afternoon tea in the Orangery,glimpse the stunning Sunken Garden and see beautiful dresses owned by Diana,Princess of Wales.Discover the glamorous and alluring world of the "Debutantes"in this new and exciting exhibition.

Admission:Adult ζ12.30.

Opening Times:Oct&from 1 Mar.Daily 10.00-18.00.Last admission 17.00.

             1 Now-28 Feb.Daily 10.00--17.00.Last admission 16.00.

Visit Time:2 hours.

Telephone:0844 482 7777.

Please see website for more information.

68In what way is Kensington Palace different from the other two places of interest?

A.Tourists can't see website for more information.

B.It's inLondon while the other two are not.

C.It won't be closed on Mnnday and Tuesdays.

D.Tourists will pay less but have more visit time

69.What makes Benjiamin Franklin House special?

A.It offers afternoon tea for tourists  B.It's the only remaining Franklin home

C.It charges free for group tourists

DIt's closer to Kensington Palace.

70.Kensington Palace is a place of interest where______.

A.a young Victoria used to live

B.tourists can experience historical moments

C.Diana used to store her dresses

D.tourists can get information by telephone

71.Three adult tourists now have 20 pounds.They can visit________together.

A.Apsley  House  B.Benjamin Franklin House

C.Kensington Palace  D.none of the three places

E

     The intelligence of the dog is among the highest of all the animals,maybe higher than we give him credit for.Although his brain is only half as large as ours,he is certainly the most intelligent of domestic animals.

A scientist in Brazil has proven dogs can count.He used a technique which also proved that 5 month old infants can count:

"He placed treats in a bowl,hid it with a screen and let the animals watch as he removed or added some.The dogs studied the contents longer when the screen was taken away if a trick had been played leaving more or less treats than expected .He tasted 11 mongrels(雜種狗)and found they paid little attention when one plus one resulted in two treats.But they looked more closely when one plus one left three."

Memory is an important component of intelligence.The dog's memory for scents is extraordinary.His visual memory is only fair,but his memory for sounds is very good,since he can remember and identify familiar voices even after an absence of many years .While he builds up a large store of identifiable sounds without the slightest effort,remembering different words requires more concentration.

The dog's capacity for learning is more a matter of memory than of true understanding.He will remember the sequence of cause and effect in his actions,but he is unable to draw broad conclusions from his experience.The greater the variety of experiences and contact with others they have,the quicher they learn,and the more they retain.

Dogs are bound by nature to remain intellectually inferior to (劣于)man,but we owe them a chance todevelop their native intelligence by training,teaching,and working with them as much and as often as we can.

72This text focuses on dog's________

A.appearances and behavious  B.intelligence and memory

C.breeds and reactions  D.emotions and attitudes

73What does the experiment by the brazilian scientist show?

A.Dogs remain intellectually inferior to man

B.Dogs' brain is only half as large as human beings'

C.Dogs know the numbers if their attemtion is drawn

D.Dogs have the same intelligence as 5-month-old infants

74How does the dog recognize the owner after he has been away for quite a long time?

A.It has memory for scents and voice

B.It has true understanding of its owner

C.It has extraordinary visual memory

D.It often misses its owner and remembers him

75This text is most probably______

A.a book review  B.a travel journal  C.a research report  D.an animal test

   A few days ago,Miss Wang was going home by bike.While he was76_________

Riding in the street,she saw the man with a knife in his hand and his77________

Face covering with a piece of cloth running towards her.The man78_______

Took her handbag out of the basket of his bike and ran away before79______

She could do anything.There was no one she could turn for help at t80_______

hat time,for it was very late at night.Luckyshe had her mobile 81_____

Phone at hand.Immediately when she took it out and phoned the82______

police.She told them what the man was like and in which directions83_____

He had run.The police came very quickly and catch the robber.Miss84____

Wang got her hangbag back and felt very grateful for the police had85____

Done for her.

書(shū)面表達(dá)

     最近,教育部等三部委聯(lián)合發(fā)出了“億萬(wàn)學(xué)生冬季長(zhǎng)跑活動(dòng)”的通知。通知內(nèi)容如下表格。

時(shí)間

2008年10月26日到次年4月30日

小學(xué)生

1000米/天

初中生

1500米/天

高中生以及大學(xué)生

2000米/天

通知發(fā)出后,人們對(duì)此有不同的觀點(diǎn)。請(qǐng)你結(jié)合實(shí)際,寫(xiě)一篇100詞左右的英語(yǔ)短文,談?wù)勀銓?duì)此項(xiàng)活動(dòng)的看法并提出建議。

    The Ministry of Education has issued a regulation,which requires students,all of the country,to participate in"Long Distance Running in Winter:.________________________

 

 

 

 

 

2009年河南省普通高中畢業(yè)班教學(xué)質(zhì)量調(diào)研考試

試題詳情

1

2

3

4

5

6

7

8

9

10

11

12

BD

AC

BD

CD

AC

C

BD

D

BC

ABC

D

B

二輪專項(xiàng):選擇2

 

1.已知氦離子He+能級(jí)與量子數(shù)的關(guān)系和氫原子能級(jí)公式類似,處于基態(tài)的氦離子He+的電離能為=54.4eV。為使處于基態(tài)的氦離子He+處于激發(fā)態(tài),入射光子所需的能量可能為(氫原子能級(jí)公式):( BD )

   A.13.6 eV       B.40.8 eV         C.48.0 eV         D.51.0 eV

2.愛(ài)因斯坦在相對(duì)論研究取得進(jìn)展的時(shí)候,提出了質(zhì)量和能量相互聯(lián)系的質(zhì)能方程:E=mc2。這個(gè)方程告訴我們,物體的能量跟它的質(zhì)量之間存在著簡(jiǎn)單的正比關(guān)系,當(dāng)物體能量改變時(shí),必定伴隨著質(zhì)量變化。由于太陽(yáng)不斷輻射能量,關(guān)于太陽(yáng)系可能發(fā)生的變化下列說(shuō)法正確的是:(AC)

A、地球公轉(zhuǎn)周期會(huì)變大             B、地球公轉(zhuǎn)周期會(huì)變小

C、太陽(yáng)系會(huì)膨脹          D、太陽(yáng)系會(huì)縮小

3.如圖所示電路中兩個(gè)光電管的陰極是由同種金屬材料制成的,現(xiàn)用強(qiáng)度相同的兩束光分別照射兩個(gè)光電管的陰極,紫光照在甲電路的光電管上,綠光照在乙電路的光電管上,若都能產(chǎn)生光電效應(yīng),則下列判斷中正確的是:(BD)

A、從兩個(gè)極板射出的光電子的最大初動(dòng)能相同,

B、甲光電管中打到陽(yáng)極上的光電子的最大初動(dòng)能一定大于乙光電管中打到陽(yáng)極上的光電子的最大初動(dòng)能,

C、單位時(shí)間內(nèi)由兩光電管產(chǎn)生的光電子的數(shù)量相同,

D、單位時(shí)間內(nèi)由乙光電管產(chǎn)生的光電子的數(shù)量比甲光電管產(chǎn)生的光電子的數(shù)量多。

4.我國(guó)西昌衛(wèi)星發(fā)射基地有一顆待發(fā)通訊衛(wèi)星,發(fā)射前隨地球一起自轉(zhuǎn)做圓周運(yùn)動(dòng),設(shè)所受向心力為F1,向心加速度為a1,角速度為ω1,動(dòng)能為E1;成功發(fā)射后繞地球在同步軌道上做勻速圓周運(yùn)動(dòng),設(shè)此時(shí)所受向心力為F2,向心加速度為a2,角速度為ω2,動(dòng)能為E2。下列關(guān)系正確的是::( CD )

A. F1>F2            B.  a=a2              C.E1< E2          D. ω12

5.在粗糙的不平地面上,一物體在水平拉力F的作用下勻加速直線運(yùn)動(dòng)。加速度大小為a,物體的質(zhì)量和物體與地面間的動(dòng)摩擦因數(shù)一定,運(yùn)動(dòng)中若將拉力F的大小減半,物體以后的運(yùn)動(dòng)情況可能是:( AC )

A.勻減速直線運(yùn)動(dòng),加速度的大小仍為a  B.勻加速直線運(yùn)動(dòng),加速度的大小仍為a

C.勻減速直線運(yùn)動(dòng),加速度大小為a/2     D.勻加速直線運(yùn)動(dòng),加速度的大小為a/2

6.(梅州08二模)某同學(xué)站在電梯里,啟動(dòng)電梯,從一樓上到十樓,以向上為正方向,下圖中t1表示電梯啟動(dòng)的時(shí)刻,t2表示剛到十樓的時(shí)刻,則能反映電梯對(duì)該同學(xué)的支持力隨時(shí)間變化關(guān)系的是:( C )

7某人在水平路面上騎著自行車轉(zhuǎn)彎(做勻速圓周運(yùn)動(dòng))時(shí),人和車身向圓心傾斜,以下說(shuō)法正確的是:( BD )

 。粒铰访鎸(duì)車身彈力的方向沿車身方向斜向上

  B.水平路面對(duì)車身彈力的方向垂直于水平路面豎直向上

 。茫铰访鎸(duì)車輪的靜摩擦力和斜向上的彈力的合力作向心力

  D.僅由水平路面對(duì)車輪的靜摩擦力作向心力

2,4,6

A.木箱克服重力所做的功等于木箱機(jī)械能的增加

B.F對(duì)木箱做的功等于木箱增加的動(dòng)能與木箱克服摩擦力所做的功之和

C.F對(duì)木箱做的功等于木箱克服摩擦力和克服重力所做的功之和

D.F對(duì)木箱做的功等于木箱增加的機(jī)械能與木箱克服摩擦力做的功之和

9.(深圳08二模)如圖所示,一內(nèi)外側(cè)均光滑的半圓柱槽置于光滑的水平面上.槽的左側(cè)有一豎直墻壁.現(xiàn)讓一小球(可是為質(zhì)點(diǎn))自左端槽口A點(diǎn)的正上方從靜止開(kāi)始下落,與半圓槽相切并從A點(diǎn)入槽內(nèi).則下列說(shuō)法正確的是:( BC )

A.小球在槽內(nèi)運(yùn)動(dòng)的全過(guò)程中,只有重力對(duì)小球做功

B.小球在槽內(nèi)運(yùn)動(dòng)的全過(guò)程中,小球與槽組成的系統(tǒng)機(jī)械能守恒

C.小球從最低點(diǎn)向右側(cè)最高點(diǎn)運(yùn)動(dòng)的過(guò)程中,小球與槽組成的系統(tǒng)水平方向上的動(dòng)量守恒

D.小球離開(kāi)右側(cè)槽口以后,將做豎直上拋運(yùn)動(dòng)

10.(佛山08調(diào)研)給平行板電容器充電,斷開(kāi)電源后A極板帶正電,B極板帶負(fù)電。板間有一帶電小球C用絕緣細(xì)線懸掛,如圖所示。小球靜止時(shí)與豎直方向的夾角為θ,則:( ABC )

A.若將B極板向右平移稍許,電容器的電容將減小

B.若將B極板向下平移稍許,A、B兩板間電勢(shì)差將增大

C.若將B極板向上平移稍許,夾角θ將變大

D.輕輕將細(xì)線剪斷,小球?qū)⒆鲂睊佭\(yùn)動(dòng)

11.(清遠(yuǎn)08一模)有四個(gè)電動(dòng)勢(shì)相同,內(nèi)阻分別為1Ω、2Ω、3Ω、4Ω的電池,分別用它們給阻值為4Ω的電阻用電器供電.欲使用電器上的電功率最大,則應(yīng)選用電池的內(nèi)阻是:( D )

A、8Ω            B、4Ω             C、2Ω            D、1Ω

12.矩形線圈abcd在勻強(qiáng)磁場(chǎng)中逆時(shí)針勻速轉(zhuǎn)動(dòng)時(shí),線圈中產(chǎn)生如圖正弦交流電,設(shè)沿aàbàcàdàa方向?yàn)殡娏髡较,則對(duì)應(yīng)圖中t時(shí)刻的線圈位置是:( B )

 

 

試題詳情

1

2

3

4

5

6

7

8

9

10

11

12

D

AD

D

A

B

B

B

CD

A

AC

D

D

二輪專項(xiàng):選擇1

 

1.物理學(xué)中研究問(wèn)題有多種方法,有關(guān)研究問(wèn)題的方法敘述錯(cuò)誤的是:( D )

A.在現(xiàn)實(shí)生活中不存在真正的質(zhì)點(diǎn),將實(shí)際的物體抽象為質(zhì)點(diǎn)是物理學(xué)中一種重要的科學(xué)研究方法

B.探究加速度a與力F、質(zhì)量m之間的關(guān)系時(shí),保持m恒定的情況下,探究a與F的關(guān)系, 采用的是控制變量法

C.電場(chǎng)強(qiáng)度的定義式,采用的是比值法

D.伽利略比薩斜塔上的落體實(shí)驗(yàn),采用的是理想實(shí)驗(yàn)法

2.從圖象中獲取信息是同學(xué)們必須掌握的能力之一。對(duì)下列各圖蘊(yùn)含的信息正確解讀是:( AD )

           

          A.圖甲說(shuō)明物體所受的重力跟它的質(zhì)量成正比

          B.圖乙表示物體正以5m/s的速度作變速運(yùn)動(dòng)

          C.圖丙告訴我們小燈泡的電阻值是固定不變的

          D.圖丁警示我們一個(gè)多世紀(jì)以來(lái)人類能源消耗急劇增長(zhǎng)

          3.氫原子的核外電子從距核較近的軌道躍遷到距核較遠(yuǎn)的軌道過(guò)程中:( D )

            A.原子要吸收光子,電子的動(dòng)能增大,原子的電勢(shì)能增大,原子的能量增大

            B.原子要放出光子,電子的動(dòng)能減小,原子的電勢(shì)能減小,原子的能量也減小

            C.原子要吸收光子,電子的動(dòng)能增大,原子的電勢(shì)能減小,原子的能量增大

            D.原子要吸收光子,電子的動(dòng)能減小,原子的電勢(shì)能增大,原子的能量增大

          4.一以接近光速相對(duì)地球飛行的宇宙飛船,在地球上觀察到飛船長(zhǎng)度縮短,在飛船中將觀察到地球上的長(zhǎng)度:( A )

          A.縮短   B.伸長(zhǎng)    C.不變   D.無(wú)法確定

          5.太陽(yáng)里的熱核反應(yīng)方程為:下列說(shuō)法正確的是:( B )

          A.2 1H和3 1H是兩種不同元素的原子核

          B.2 1H和3 1H是氫的兩種同位素的原子核

          C.這個(gè)反應(yīng)既是核反應(yīng),也是化學(xué)反應(yīng)

          D.這個(gè)反應(yīng)過(guò)程中反應(yīng)前核的總質(zhì)量小于反應(yīng)后核的總質(zhì)量

          6.圖示為高速攝影機(jī)拍攝到的子彈穿透蘋(píng)果瞬間的照片。該照片經(jīng)放大后分辨出,在曝光時(shí)間內(nèi),子彈影象前后錯(cuò)開(kāi)的距離約為子彈長(zhǎng)度的1%~2%。已知子彈飛行速度約為500m/s,由此可估算出這幅照片的曝光時(shí)間最接近:( B )

          A.10-3s       B.10-6s       C.10-9s       D.10-12s

          7.如圖所示,一根細(xì)線一端固定在容器底部,另一端系一木球,木球浸沒(méi)在水中,整個(gè)裝置在臺(tái)秤上。現(xiàn)將細(xì)線割斷,在木球上浮的過(guò)程中(不計(jì)水的阻力),臺(tái)秤示數(shù)將:(  B  )

          A.增大                 B.減小     

          C.不變                 D.無(wú)法確定

          8.我國(guó)自主研制的“神七”載人飛船于2008年9月25日21時(shí)10分04秒,在酒泉衛(wèi)星發(fā)射中心成功發(fā)射。第583秒火箭將飛船送到近地點(diǎn)200km,遠(yuǎn)地點(diǎn)350km的橢圓軌道的入口,箭船分離。21時(shí)33分變軌成功,飛船進(jìn)入距地球表面約343km的圓形預(yù)定軌道,繞行一周約90分鐘,關(guān)于“神七”載人飛船在預(yù)定軌道上運(yùn)行時(shí)下列說(shuō)法中正確的是:(CD)

          A.“神七”載人飛船可以看作是地球的一顆同步衛(wèi)星

          B.飛船由于完全失重,飛船中的宇航員不再受到重力的作用

          C.當(dāng)飛船要離開(kāi)圓形軌道返回地球時(shí),要啟動(dòng)助推器讓飛船速度減小

          D.飛船繞地球運(yùn)行的角速度比月球繞地球運(yùn)行的角速度大

          9.如右圖所示,O點(diǎn)為等量異種點(diǎn)電荷連線的中點(diǎn),a、b兩點(diǎn)的連線與兩電荷連線垂直。今在外力作用下將帶電量為+q的點(diǎn)電荷從a點(diǎn)移動(dòng)到b點(diǎn),關(guān)于點(diǎn)電荷的電勢(shì)能下列說(shuō)法中正確的是:( A )

          A.增加                B.減少 

          C.不變                D.無(wú)法判斷

          10.某同學(xué)在學(xué)習(xí)了法拉第電磁感應(yīng)定律之后,自己制作了一個(gè)手動(dòng)手電筒,如圖是手電筒的簡(jiǎn)單結(jié)構(gòu)示意圖,左右兩端是兩塊完全相同的條形磁鐵,中間是一根絕緣直桿,由絕緣細(xì)銅絲繞制的多匝環(huán)形線圈只可在直桿上自由滑動(dòng),線圈兩端接一燈泡,晃動(dòng)手電筒時(shí)線圈也來(lái)回滑動(dòng),燈泡就會(huì)發(fā)光,其中O點(diǎn)是兩磁極連線的中點(diǎn),ab兩點(diǎn)關(guān)于O點(diǎn)對(duì)稱,則下列說(shuō)法中正確的是:( AC )

          A.線圈經(jīng)過(guò)O點(diǎn)時(shí)穿過(guò)的磁通量最小

          B.線圈經(jīng)過(guò)O點(diǎn)時(shí)受到的磁場(chǎng)力最大

          C.線圈沿不同方向經(jīng)過(guò)b點(diǎn)時(shí)所受的磁場(chǎng)力方向相反

          D.線圈沿同一方向經(jīng)過(guò)ab兩點(diǎn)時(shí)其中的電流方向相同

          11.某研究性學(xué)習(xí)小組用加速度傳感器研究物體從靜止開(kāi)始做直線運(yùn)動(dòng)的規(guī)律,得到了物體的加速度隨時(shí)間變化的關(guān)系圖線,如圖6所示。已知物體的質(zhì)量為1.0kg,則下列說(shuō)法正確的是:( D )

          A.物體在t =2.0s到t =4.0s這段時(shí)間內(nèi)做勻減速直線運(yùn)動(dòng)

          B.不能從已知信息粗略估算出物體在t=3.0s時(shí)的速度

          C.不能從已知信息粗略估算出物體從t=1.0s到t=4.0s這段時(shí)間內(nèi)所受合外力的沖量

          D.可以從已知信息粗略估算出物體從t=1.0s到t=4.0s這段時(shí)間內(nèi)所受合外力對(duì)物體做的功

          12.如圖4所示,理想變壓器原、副線圈的匝數(shù)比為k,輸出端接有一交流電動(dòng)機(jī),其線圈的電阻為R。將原線圈接在正弦交流電源兩端,變壓器的輸入功率為P0時(shí),電動(dòng)機(jī)恰好能帶動(dòng)質(zhì)量為m的物體以速度v勻速上升,此時(shí)理想電流表A的示數(shù)為I。若不計(jì)電動(dòng)機(jī)的機(jī)械能損耗,重力加速度為g,則下列說(shuō)法正確的是:( D )

          A.電動(dòng)機(jī)輸出的機(jī)械功率為P0

          B.變壓器的輸出功率為mgv

          C.副線圈兩端電壓的有效值為

          D.整個(gè)裝置的效率為

           

           

          試題詳情

          2009屆漳州三中高三質(zhì)量檢測(cè)

           理科綜合能力測(cè)試(五) 

          本試卷分第I卷(選擇題)和第II卷。第I卷均為必考題,第II卷包括必考和選考兩個(gè)部分?荚嚂r(shí)間150分鐘,總分300分。

          相對(duì)原子質(zhì)量:O-16   Na-23   Ba-137

           

          I卷  (必考)

          本卷共18小題,每小題6分,共108分。

          試題詳情

          漳浦二中高三物理第二輪模擬卷(一)

          13.如圖3 ? 5所示,一條易斷的均勻細(xì)繩兩端固定在天花板上的A、B兩點(diǎn),今在繩上某點(diǎn)O處固定懸掛砝碼,使AO > BO,則

                 A.增加砝碼時(shí),AO先斷         

          B.增加砝碼時(shí),BO先斷

          C.B點(diǎn)向左移,繩子易斷

          D.B點(diǎn)向右移,繩子易斷

          14.如圖3 ? 1所示,質(zhì)量分別為10 kg的物體AB通過(guò)滑輪與物體C相連,物體與水平面和斜遄間的動(dòng)摩擦因數(shù)均為0.2,斜面的傾角為37°。若C剛好能勻速拉動(dòng)AB下滑,則物體C的質(zhì)量為(重力加速度g10 m/s2

                 A.9.6 kg             B.8.0 kg

                 C.3.6 kg             D.7.6 kg     

          15. 1990年5月,紫金山天文臺(tái)將他們發(fā)現(xiàn)的第2752號(hào)小行星命名為吳健雄星,該小行星的半徑為16km。若將此小行星和地球均看成質(zhì)量分布均勻的球體,小行星密度與地球相同。已知地球半徑km,地球表面重力加速度為g。這個(gè)小行星表面的重力加速度為

          A. 400g     B.      C. 20g     D.

           

          16.一列橫波沿x軸正向傳播,在介質(zhì)中只存在四分之三波長(zhǎng)的波形,某時(shí)刻恰好到達(dá)坐標(biāo)原點(diǎn)處,如圖3 ? 13所示。此波傳到x = 20 cmP點(diǎn)時(shí),處于原點(diǎn)O的質(zhì)點(diǎn)所通過(guò)的路程式和該時(shí)刻的位移分別為

                 A.40 cm  0 cm                               B.6 cm  2 cm

                 C.20 cm  0 cm                               D.6 cm  ? 2 cm 

          17.如圖3 ? 30所示,一束單色光a沿半徑射向置于空氣中的半球形玻璃磚的球心,在界面M上同時(shí)發(fā)生反射和折射,b為反射光,c為折射光,它們與法線的夾角分別為。逐漸增大入射角(但小于臨界角),則下列說(shuō)法中正確的是

                 A.兩角同時(shí)增大,始終大于

                 B.b光束的亮度逐漸減弱,c光束的亮度逐漸增強(qiáng)

                 C.b光在玻璃中的波長(zhǎng)小于c光的波長(zhǎng)

                 D.b光光子的能量大于c光光子的能量  

          18.如圖3 ? 24所示,動(dòng)圈式話筒能夠?qū)⒙曇艮D(zhuǎn)變?yōu)槲⑷醯碾娦盘?hào)(交變電流),產(chǎn)生的電信號(hào)一般都不是直接送給擴(kuò)音機(jī),而是經(jīng)過(guò)一只變壓器之后再送給護(hù)音機(jī)放大,變壓器的作用是減少信號(hào)沿導(dǎo)線傳輸過(guò)程中的電能損失,關(guān)于話筒內(nèi)的這只變壓器,下列說(shuō)法中正確的是

                 A.一定是升壓變壓器,因?yàn)?i>P = UI,升壓后,電流減小,導(dǎo)線上損失的電能

          減少

                 B.一定不是升壓變壓器,因?yàn)?i>P = U2/R,升壓后,導(dǎo)線上損失的電能會(huì)增加

                 C.一定是降壓變壓器,因?yàn)?i>I2 = n1I1 / n2,降壓后,電流增大,使到達(dá)擴(kuò)音機(jī)

          的信號(hào)加強(qiáng)

                 D.一定不是降壓變壓器,因?yàn)?i>P = I 2R,降壓后,電流增大,導(dǎo)線上損失的

          電能會(huì)增加

          試題詳情

          本資料來(lái)源于《七彩教育網(wǎng)》http://www.7caiedu.cn

          《推理、證明與數(shù)學(xué)歸納法》

           

          試題詳情

          漳浦二中高三物理第二輪模擬卷(二)

          13.一質(zhì)量為1kg的物體被人用手由靜止向上提高了1m,這時(shí)物體的速度是2m/s,下列說(shuō)法中正確的是(g取10 m/s2)  (  ACD )

              A.手對(duì)物體做功12J                  B.合外力對(duì)物體做功12J

              C.合外力對(duì)物體做功2J               D.物體克服重力做功10J

          14.據(jù)報(bào)道,嫦娥二號(hào)探月衛(wèi)星將于2010年發(fā)射,其環(huán)月飛行的高度距離月球表面100km,所探測(cè)到的有關(guān)月球的數(shù)據(jù)將比環(huán)月飛行高度為200km的嫦娥一號(hào)更加翔實(shí)。若兩顆衛(wèi)星環(huán)月運(yùn)行均可視為勻速圓周運(yùn)動(dòng),運(yùn)行軌道如圖所示。則               B

          A.嫦娥二號(hào)環(huán)月運(yùn)行的周期比嫦娥一號(hào)更大

          B.嫦娥二號(hào)環(huán)月運(yùn)行的周期比嫦娥一號(hào)更小

          C.嫦娥二號(hào)環(huán)月運(yùn)行時(shí)向心加速度比嫦娥一號(hào)更小

          D.嫦娥二號(hào)環(huán)月運(yùn)行時(shí)向心加速度與嫦娥一號(hào)相等

          15.一個(gè)理想變壓器,原線圈和副線圈的匝數(shù)分別為n1和n2,正常工作時(shí)輸入和輸出的電壓、電流、功率分別為U1和U2、I1和I2、P1和P2,已知n1>n2,則  (BC   )                                              

          A.U1>U2,P1<P2                                                                B.P1=P2 ,I1<I2,

          C.I1<I2,U1>U2                                                                     D.P1>P2,I1>I2

          16.如圖所示,一束單色光射入一玻璃球體,入射角為600。己知光線在玻璃球內(nèi)經(jīng)一次反射后,再次折射回到空氣中時(shí)與入射光線平行。此玻璃的折射率為         B            

              A.2    B.

          C.1.5    D.

          17.一列簡(jiǎn)諧波沿一直線向左運(yùn)動(dòng),當(dāng)直線上某質(zhì)點(diǎn)a向上運(yùn)動(dòng)到達(dá)最大位移時(shí),a點(diǎn)右方相距0.15m的b點(diǎn)剛好向下運(yùn)動(dòng)到最大位移處,則這列波的波長(zhǎng)可能是   ( BD  )

          A.0.6m                B.0.3m

               C.0.2m                D.0.1m

          18.矩形導(dǎo)線框abcd固定在勻強(qiáng)磁場(chǎng)中,磁感線的方向與導(dǎo)線框所在平面垂直,規(guī)定磁場(chǎng)的正方向垂直紙面向里,磁感應(yīng)強(qiáng)度B隨時(shí)間t變化的規(guī)律如圖所示。若規(guī)定順時(shí)針?lè)较驗(yàn)楦袘?yīng)電流i的正方向,下列i-t圖像中正確的是  D

           

           

          19、(1)(9分)衛(wèi)星繞地球做勻速圓周運(yùn)動(dòng)時(shí)處于完全失重狀態(tài),

          物體對(duì)支持面幾乎沒(méi)有壓力,所以在這種環(huán)境中已無(wú)法用

          天平稱量物體的質(zhì)量。假設(shè)某同學(xué)在這種環(huán)境設(shè)計(jì)了如圖

          所示的裝置(圖中O為光滑的小孔)來(lái)間接測(cè)量物體的質(zhì)            

          量:給待測(cè)物體一個(gè)初速度,使它在桌面上做勻速圓周運(yùn)

          動(dòng)。設(shè)航天器中具有基本測(cè)量工具。                        

                  ①物體與桌面間的摩擦力可以忽略不計(jì),原因是                         ;

                  ②實(shí)驗(yàn)時(shí)需要測(cè)量的物理量是                                        ;

                  ③待測(cè)質(zhì)量的表達(dá)式為m=                 。

          答案:物體與接觸面間幾乎沒(méi)有壓力,摩擦力幾乎為零(3分);

                     彈簧秤示數(shù)F、圓周運(yùn)動(dòng)的半徑R、圓周運(yùn)動(dòng)的周期T(3分);

                     FT2/4(3分)

          (2)(9分)圖1中電源電動(dòng)勢(shì)為E,內(nèi)阻可忽略不計(jì);電流表   具有一定的內(nèi)阻,電壓表    的內(nèi)阻不是無(wú)限大,S為單刀雙擲開(kāi)關(guān),R為待測(cè)電阻。當(dāng)S向電壓表一側(cè)閉合時(shí),電壓表讀數(shù)為U1,電流表讀數(shù)為I1;當(dāng)S向R一側(cè)閉合時(shí),電流表讀數(shù)為I2。

              ⑴根據(jù)已知條件與測(cè)量數(shù)據(jù),可以得出待測(cè)電阻R=           。

              ⑵根據(jù)圖1所給出的電路,在圖2的各器件實(shí)物圖之間畫(huà)出連接的導(dǎo)線。

           

           

           

           

           

           

           

           

           

           

          19、 連線如圖

           

           

           

           

           

           

          20.(15分)如圖所示,物體A重10N,物體與豎直墻的動(dòng)摩擦因系數(shù)為0.4,用一個(gè)與水平方向成37°角的力F作用在物體上,要使物體A沿墻向下作勻速運(yùn)動(dòng)則該力的大小為多大?(g取10m/s2,sin37°=0.6,結(jié)果保留兩位有效數(shù)字)

           

          20.(15分)

          A沿豎直墻面向下勻速時(shí):

          F2sin37°+Ff2-G=0

          F2cos37°-FN2=0

          Ff2=μFN2

          F2==10.9(N)

          故所求的力的大小為10.9N

           

          21. (19分)下表是一輛電動(dòng)自行車的部分技術(shù)指標(biāo),其中額定車速是指電動(dòng)車滿載情況下在平直道路上以額定功率勻速行駛的速度。

          額定

          車速

          載車

          質(zhì)量

          載重

          電源

          電源輸

          出電壓

          充電

          時(shí)間

          額定輸出

          功率

          電動(dòng)機(jī)額定工作電壓和電流

          18km/h

          40kg

          80kg

          36V/12Ah

          ≥36V

          6~8h

          180W

          36V/6A

            請(qǐng)參考表中數(shù)據(jù),完成下列問(wèn)題(g取10 m/s2):

             (1)此車所配電動(dòng)機(jī)的內(nèi)阻是多少?

             (2)在行駛過(guò)程中電動(dòng)機(jī)受阻力是車重(包括載重)的K倍,試計(jì)算K的大小。

             (3)若電動(dòng)車滿載時(shí)以額定功率行駛,當(dāng)車速為3m/s時(shí)的加速度為多少?

          解:(1)從表中可知,輸出功率P= 180W,

          輸入功率P=UI=36×6W=216W     ①      Pr=I2r=P-P出          

          r =          ③

             (2)P=f=K(M+m)g    ④    K=      ⑤

             (3) P=F                  ⑥    F-K(M+m)g=(M+m)a       ⑦

          由⑥、⑦得:a=0.2米/秒2   

           

          22.(20分)核聚變反應(yīng)需要幾百萬(wàn)度以上的高溫,為了把高溫條件下高速運(yùn)動(dòng)的離子約束在小范圍內(nèi),通常采用磁約束的方法(托卡馬克裝置),F(xiàn)用下述簡(jiǎn)化的模型來(lái)研究這一問(wèn)題,如圖所示,兩個(gè)同心圓為勻強(qiáng)磁場(chǎng)的內(nèi)外邊界,,,磁場(chǎng)方向垂直紙面向里,已知帶正電粒子的比荷,勻強(qiáng)磁場(chǎng)的磁感應(yīng)強(qiáng)度,帶正電的粒子以某一速度v從內(nèi)邊界上的A點(diǎn)射入磁場(chǎng)區(qū)域。不考慮帶電粒子因高速運(yùn)動(dòng)產(chǎn)生的相對(duì)論效應(yīng)。

          (1)導(dǎo)出帶電粒子在磁場(chǎng)區(qū)域中作圓周運(yùn)動(dòng)的軌道半徑r與上述各量的關(guān)系式(用已知量字母代號(hào)q.m.B.v表示);

          (2)若上述帶電粒子從A點(diǎn)沿半徑方向射入磁場(chǎng)區(qū)域恰好不穿出外邊界,請(qǐng)?jiān)趫D中畫(huà)出粒子的運(yùn)動(dòng)軌跡示意圖;

          (3)若大量上述粒子從A點(diǎn)沿各個(gè)方向射入磁場(chǎng)區(qū)域,求所有粒子均不穿出磁場(chǎng)區(qū)域外邊界時(shí)粒子的最大速度v0。

           

           

           

           

           

           

          22.(20分)

          (1)帶電粒子從A點(diǎn)射入磁場(chǎng)區(qū)域后,由牛頓運(yùn)

          動(dòng)定律和向心力公式得

                    ①     (2分)

          ∴           ②     (2分)

          (2)粒子運(yùn)動(dòng)軌跡如圖1所示。  (6分)

          (3)由①式得帶電粒子運(yùn)動(dòng)速率 ,即v與r成正比。

          由題意可知,該粒子從A點(diǎn)射入磁場(chǎng)區(qū)域又不離開(kāi)磁場(chǎng)外邊界的最小可能軌道半徑(如圖2)

                        ③    (4分)

          由此可得粒子從A點(diǎn)射入磁場(chǎng)區(qū)域又不離開(kāi)磁場(chǎng)

          外邊界的允許的最大速率

                          ④    (2分)

                 ⑤    (2分)

          代入數(shù)據(jù)解得    ⑥  (2分

          29.(12分)【物理3―5】(1) 紫外線照射到一些物質(zhì)時(shí),會(huì)發(fā)生熒光效應(yīng),即物質(zhì)發(fā)出可見(jiàn)光。這些物質(zhì)中的原子先后發(fā)生兩次躍遷,其能量變化分別為△El和△E2,下列關(guān)于原子這兩次躍遷的說(shuō)法中正確的是           。(填選項(xiàng)前的編號(hào))       ③

                ①兩次均向高能級(jí)躍遷,且  

                ②兩次均向低能級(jí)躍遷,且

                ③先向高能級(jí)躍遷,再向低能級(jí)躍遷,且

                ④先向高能級(jí)躍遷,再向低能級(jí)躍遷,且

          (2)如圖所示的裝置中,木塊B與水平桌面間的接觸是光滑的,子彈A沿水平方向射入木塊后留在木塊內(nèi),將彈簧壓縮到最短.現(xiàn)將子彈.木塊和彈簧合在一起作為研究對(duì)象(系統(tǒng)),則此系統(tǒng)在從子彈開(kāi)始射入木塊到彈簧壓縮至最短的整個(gè)過(guò)程中
             A.動(dòng)量守恒.機(jī)械能守恒
             B.動(dòng)量不守恒.機(jī)械能不守恒
             C.動(dòng)量守恒.機(jī)械能不守恒
             D.動(dòng)量不守恒.機(jī)械能守恒              B

           

           

           

           

           

          試題詳情


          同步練習(xí)冊(cè)答案