分析:根據(jù)反比例函數(shù)判斷出k的取值,進而判斷出一次函數(shù)所在象限即可.
解答:解:A、由反比例函數(shù)圖象可得k<0,∴一次函數(shù)y=kx-k應經(jīng)過一二四象限,故A選項錯誤;
B、由反比例函數(shù)圖象可得k>0,∴一次函數(shù)y=kx-k應經(jīng)過一三四象限,故B選項正確;
C、由反比例函數(shù)圖象可得k<0,∴一次函數(shù)y=kx-k應經(jīng)過一二四象限,故C選項錯誤;
D、由反比例函數(shù)圖象可得k>0,∴一次函數(shù)y=kx-k應經(jīng)過一三四象限,故D選項錯誤;
故選:B.
點評:綜合考查了反比例函數(shù)和一次函數(shù)的圖象特征;用到的知識點為:一次函數(shù)的比例系數(shù)大于0,一次函數(shù)經(jīng)過一三象限,常數(shù)項大于0,還經(jīng)過第二象限;常數(shù)項小于0,還經(jīng)過第四象限;比例系數(shù)小于0,一次函數(shù)經(jīng)過二四象限,常數(shù)項大于0,還經(jīng)過第一象限,常數(shù)項小于0,還經(jīng)過第三象限;反比例函數(shù)的比例系數(shù)大于0,圖象的兩個分支在一三象限;比例系數(shù)小于0,圖象的2個分支在二四象限.