Question

游泳池常用硫酸銅溶液進(jìn)行殺菌消毒．某游泳池現(xiàn)需含銅4%的硫酸銅溶液消毒，試求這種溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)？

Answer 1

分析：可設(shè)溶液的質(zhì)量為100g，然后根據(jù)硫酸銅中銅的質(zhì)量分?jǐn)?shù)求出硫酸銅的質(zhì)量即可進(jìn)行解答．

解答：解：設(shè)CuSO₄溶液的質(zhì)量100g，則其中含銅元素的質(zhì)量為4g．
則硫酸銅的質(zhì)量=4g×

Mr(CuSO4)

Mr(Cu)

=4g×

160

64

=10g
所以硫酸銅溶液的溶質(zhì)的質(zhì)量分?jǐn)?shù)=

10g

100g

×100%=10%
答：硫酸銅溶液溶質(zhì)的質(zhì)量分?jǐn)?shù)為10%

點(diǎn)評(píng)：本題主要考查學(xué)生對(duì)元素的質(zhì)量分?jǐn)?shù)及溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)進(jìn)行簡(jiǎn)單計(jì)算的能力．